Change in April's weight is -7
<em><u>Solution:</u></em>
Let the initial weight be "x"
April lost 5 pounds in her first week of college
First week = lost 5 pounds
Therefore, x - 5
Over the next three weeks she lost 3 pounds, gained 2 pounds, and then lost 1 pound
<em><u>Next three week:</u></em>
Lost 3 pound
Gained 2 pound
Lost 1 pound
<em><u>Therefore, weight after 4 weeks is given as:</u></em>
x - 5 - 3 + 2 - 1 = x -7
After 4 week, the weight is x - 7
<em><u>The change in April weight is given as:</u></em>
Weight after 4 week - initial weight = x - 7 - x = -7
Thus change in April's weight is -7 (Negative sign represents loss in weight )
Answer:
Step-by-step explanation:84% of a contractor’s jobs involves electrical work. 75% of a contractor’s jobs involve plumbing work. Of the jobs that involve plumbing, 90% of the jobs also involves electrical work. Let E = jobs involving electrical work L = jobs involving plumbing work Suppose one of the contractor’s jobs is randomly selected. Using the sixth Excel worksheet, a) Find P(E). 0.84 b) Find P(L). 0.75 c) In words, what does E | L mean? d) Find P(E | L). e) Find P(E and L). f) Are E and L independent events? Why or why not? g) Find P(E or L). h) Are E and L mutually exclusive? Why or why not
Answer:
there are 7 days in a week x 0.10 cents saved each day on the week = 0.70 cents every week
Step-by-step explanation:
"<span>How much did your classmates typically spend on music downloads last year?" is a statistical question, and the units would </span>be both the number of students and how many downloads each individual bought.
I = $ 1,200,000.00
Equation:
I = Prt
Calculation:
First, converting R percent to r a decimal
r = R/100 = 3%/100 = 0.03 per year,
then, solving our equation
I = 1000000 × 0.03 × 40 = 1200000
I = $ 1,200,000.00
The simple interest accumulated
on a principal of $ 1,000,000.00
at a rate of 3% per year
for 40 years is $ 1,200,000.00.
