<h3>Answer:</h3>
Rb = + 1
S = + 4
O = - 2
<h3>Explanation:</h3>
Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,
Rb₂ + S + O₃ = 0
Above zero (0) means that the overall molecule is neutral.
Putting values of Rb and O,
(+1)₂ + S + (-2)₃ = 0
(+2) + S + (-6) = 0
+2 + S - 6 = 0
S - 6 = -2
S = -2 + 6
S = + 4
Answer:
a
Explanation:
the others are rude, and rather support this, while a helps to support the ending of white privlige
The electronic configuration of x, y, and z.



<h3>What is an electronic configuration?</h3>
Electronic configuration, also called electronic structure, is the arrangement of electrons in energy levels around an atomic nucleus.
a.



b.
x= Period 1 and group18
Y=Element is in period 3 and Group 2
Z=Element is in period 3 and group 17.
c.
X, Y & Z represents Helium, magnesium, and chlorine.
Learn more about the electronic configuration here:
brainly.com/question/19589767
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Answer:
2
Explanation:
First, find the hydronium ion concentration of the solution with a pH of 4.
[H₃O⁺] = 10^-pH
[H₃O⁺] = 10⁻⁴
[H₃O⁺] = 1 × 10⁻⁴
Next, multiple the hydronium ion concentration by 100 to find the hydronium ion concentration of the new solution.
[H₃O⁺] = 1.0 × 10⁻⁴ × 100 = 0.01
Lastly, find the pH.
pH = -log [H₃O⁺]
pH = -log (0.01)
pH = 2
The pH of a solution that has a hydronium ion concentration 100 times greater than a solution with a pH of 4 is 2.
Hope this helps.
H2S and HS- are a conjugate acid-base pair.