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3 years ago

What is the nuclear equation for formation of iron-54 through fusion

Chemistry

2 answers:

Luden [163]3 years ago

6 0

The nuclear equation for formation of iron-54 through fusion would be Fe + heat ----> Fe_54 + + neutrons.

Explanation:

A balanced nuclear equation is a thing where the sum of the mass numbers (the first number in system) and the sum of the atomic numbers balance on each side of an equation. Nuclear equation puzzles will often be given such that one particle is blowing.

Assoli18 [71]3 years ago

4 0

The nuclear equation for formation of iron-54 through fusion would be Fe + heat ----> Fe_54 + + neutrons. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

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Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (

aleksley [76]

Answer: The amount of heat produced by the reaction is -21.36 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol$

To calculate the number of moles, we use ideal gas equation, which is:

$PV=nRT$

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = $0.0831\text{ L. bar }mol^{-1}K^{-1}$

T = temperature of the mixture = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol$

To calculate the heat released of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

$-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ$

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0

3 years ago

There are several aromatic compounds with the formula C8H9Cl. Draw those that have a trisubstituted ring where the methyl groups

Kryger [21]

Answer:

$3-Chloro-1,2-dimethylbenzene$

$4-Chloro-1,2-dimethylbenzene$

Explanation:

Such types of compounds in which conjugated planer ring system and delocalized pi electrons are present are called aromatic compounds such as Toluene, Benzene and some other. Generally, these compounds follow Huckle's rule. The trisubstituted ring means a compound in which three hydrogen atoms are replaced by three other groups. In the given compound two hydrogen atoms are replaced by two methyl groups and one hydrogen atom is replaced by one Chlorine atom. From the given compound $3-Chloro-1,2-dimethylbenzene$ , and $4-Chloro-1,2-dimethylbenzene$ can be drawn.

7 0

3 years ago

A glycosidic bond between two monosaccharides can also be classified as a(n) ________.

Natali5045456 [20]

Here we are asked to know the type of bond between a glycosidic bond. A glycosidic bond is a type of bond that exists between a carbohydrate molecule to another carbohydrate molecule. A glycosidic bond creates between two monosaccharides can also be called as an ether bond.

8 0

3 years ago

Which has the largest atomic radius magnesium silicon sulfur or sodium the smallest

Monica [59]

Therefore the largest atoms are on the left and the smallest on the right. So sodium (Na) has the largest atomic radius, as the valence electrons are the least attracted to the nucleus

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5 0

3 years ago

Read 2 more answers

Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical

melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0

3 years ago