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Oksanka [162]
3 years ago
5

I need help with 10 math questions I will say it in chat​

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

if I'm just good at math I might be able to help you

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Felicity put down 800 on a used car. She took out a loan to pay off the balance of the cost of the car. Her monthly payment will
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She would have paid 1,575 dollars plus the 800 down payment. The total would be $2,375.
8 0
3 years ago
The water level at your dock is 5 ft above sea level. The tide goes out and the water decreases by 8 ft. What integer represents
Tanya [424]

Answer:

-3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
3(q−7)=27 need help plzz 1st peep gets brainlest
ANTONII [103]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>q = 16</em>

▹ Step-by-Step Explanation

3(q - 7) = 27

3q - 21 = 27

Add 21 to both sides:

21 + 21 = na

27 + 21 = 48

3q = 48

Divide both sides by 3:

3/3 = q

48/3 = 16

q = 16

Hope this helps!

CloutAnswers ❁

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8 0
4 years ago
Read 2 more answers
A quadrilateral can be inscribed in a circle, if and only if, the opposite angles in that quadrilateral are supplementary.
Setler [38]

The opposite angles are equal to are supplementary to each other or equal to each other.

<h3>What is a Quadrilateral Inscribed in a Circle?</h3>

In geometry, a quadrilateral inscribed in a circle, also known as a cyclic quadrilateral or chordal quadrilateral, is a quadrilateral with four vertices on the circumference of a circle. In a quadrilateral inscribed circle, the four sides of the quadrilateral are the chords of the circle.

The opposite angles in a cyclic quadrilateral are supplementary. i.e., the sum of the opposite angles is equal to 180˚.

If e, f, g, and h are the inscribed quadrilateral’s internal angles, then

e + f = 180˚ and g + h = 180˚

by theorem the central angle = 2 x inscribed angle.

∠COD = 2∠CBD

∠COD = 2b

∠COD = 2 ∠CAD

∠COD = 2a

now,

∠COD + reflex ∠COD = 360°

2e + 2f = 360°

2(e + f) =360°

e + f = 180°.

Learn more about this concept here:

brainly.com/question/16611641

#SPJ1

6 0
2 years ago
Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean len
Marina86 [1]

Answer:

Step-by-step explanation:

Hello!

You need to construct a 95% CI for the population mean of the length of engineering conferences.

The variable has a normal distribution.

The information given is:

n= 84

x[bar]= 3.94

δ= 1.28

The formula for the Confidence interval is:

x[bar]±Z_{1-\alpha/2}*(δ/n)

Lower bound(Lb): 3.698

Upper bound(Ub): 4.182

Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242

I hope it helps!

6 0
4 years ago
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