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3 years ago

Math problem please help

Mathematics

2 answers:

Vesna [10]3 years ago

5 0

Monday and Tuesday are the correct answers due to the negative number being lower than -1.75 F

laila [671]3 years ago

3 0

it should be monday any thing that smaller then -1.75 would make it hotter

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Please I need help I’m giving 20 points for the answer please

strojnjashka [21]

Answer:

I would answer but in your question you said you are giving away 20 points when you are only giving away 15.... Make sure to state facts only.

Step-by-step explanation:

I'll answer anyways.....

You can make 0 different triangles. The angles/points would never line up right to make a triangle. Sorry if I'm wrong but I'm pretty sure this is right.

*If this helped Plz mark Brainliest*

3 0

3 years ago

What are the solutions to the equation 3(x – 4)(x + 5) = 0?

iris [78.8K]

Answer:

x=4 and x= - 5

Step-by-step explanation:

In order to solve this we should re-arrange the equation:

$(x-4)(x+5)=\frac{0}{3}$

This is equal to:

$(x-4)(x+5)=0$

Then we can seperate this into:

$(x-4)=0\\(x+5)=0$

So solving for x in both cases we get

$x-4=0 \\x=4\\And\\x+5=0\\x=-5\\$

4 0

3 years ago

Who good at angles ?

Kamila [148]

Answer:

JRQ = 56

Step-by-step explanation:

SRQ - SRJ = JRQ

166 - 110 = 56

6 0

3 years ago

25 points please help me!

lianna [129]

$1.14 1.40 x 0.8=1.12 1.4+ 1.12=1.52 * 0.25 = 1.14

8 0

3 years ago

Solve for x and y. 4x-3y=16 -2x+4y=-2 DUE 2/7/17!

Trava [24]

$\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.$

Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
 $\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.$
$\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.$
--------------------
$5y = 12$
$\boxed{\boxed{y = \frac{12}{5}}}\end{array}}\qquad\quad\checkmark$

Let's replace the value found in the first equation:
$4x-3y=16\:(I)$
$4x-3*( \frac{12}{5}) =16$
$4x - \frac{36}{5} = 16$
least common multiple (5)
$\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}$
$20x - 36 = 80$
$20x = 80 + 36$
$20x = 116$
$x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark$

4 0

3 years ago