Answer:
The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams
Explanation:
The question is with regards to density calculations
The density of the given sodium carbonate solution, ρ = 0.4 g/dm³
The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³
Therefore, we have;
The mass, "m", of the sodium carbonate in = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g
The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.
Answer:D
Explanation:
Jus did this question & got it right
Answer:
C
Explanation:
okay, you need to look at the structures of the particles of matter in the solid, liquid and gas.
- particles in a solid are in fixed positions, where they can only vibrate in those positions ( take a look at ice, or rather, a brick)
- liquids have very small or rather, no spaces between them, but they can slide or rub against each other, like people in a <em>really tight</em> crowd I guess
- gas particles have very large spaces between them and they move randomly. these exibit what's called brownian motion.
- since water particles (and all other liquid particles) have negligible spacings and limited movement, that allows the dye particles to move from a region of high concentration to that of a low concentration. the aim for this is for the mixture/solution to reach an equilibrium, that is the mixture must get to a point where all regions have the same concentration of the dye.
you can refer to your coursebooks :)
correct where wrong please:)
Answer:
The anion at the end on the compound
Explanation:
to check whether a substance is soluble or not, you would find the anion at the end of the compound on a solubility chart and then see from there whether it is soluble or not
Answer:
E
C
B
D
A
Explanation:
The definition of words correspond well with the answers I provided and somewhat match with the dictionary definitions.
