Use the formula in terms of half life from the normal exponential functions
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N(t) = N(0) (1/2) ^ (t/thalf) </span>
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N(0) is the original quantity </span>
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N(t) = quantity remaining at time t </span>
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t is the time </span>
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thalf is half life </span>
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1/16 = (1/2)^(t/3.82) </span>
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16 = 2^(t/3.82) </span>
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4 = t/3.82 </span>
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t = 15.28 days
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Answer:
Copper(II) sulphate – sodium hydroxide reaction
The reaction between copper(Il) sulphate and sodium hydroxide solutions is a good place to start. If you slowly add one to the other while stirring, you will get a precipitate of copper(II) hydroxide, Cu(OH)2.
2.43*1000.
There are 1000 grams in a kilogram
