A. If motion starts and stops at the same location, then the displacment is zero.
D. Distance is always greater than or equal to the magnitutde of the displacement.
First, we need the no.of moles of O2 = mass/molar mass of O2
= 55 g / 32 g/mol
= 1.72 mol
from the balanced equation of the reaction:
2H2 (g) + O2(g) → 2H2O(g)
we can see that the molar ratio between O2: H2O = 1: 2
So we can get the no.of moles of H2O = 2 * moles of O2
= 2 * 1.72 mol
= 3.44 mol
So by substitution by this value in ideal gas formula:
PV = nRT
when P = 12.4 atm & n H2O = 3.44 mol & R= 0.0821 & T = 85 + 273=358K
12.4 atm *V = 3.44 * 0.0821 * 358 = 8.15 L
∴ V ≈ 8.2 L
Answer:
2:1<em><u> </u></em><em><u> </u></em><em><u>of </u></em><em><u> </u></em><em><u>Tc </u></em><em><u>in </u></em><em><u>the</u></em><em><u> </u></em><em><u>periodic</u></em><em><u> table</u></em>
Proton: positive- mass equal to neutron
Electron: negative- mass 1/1840 mass of proton
Neutron: no charge- same mass as proton
Answer:
1 in. =2.54 cm
3*(10^-4)*2.54=7.62*10^-4
Explanation:
