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3 years ago

Why can't we say that acids react with all metals to produce hydrogen ?

Chemistry

2 answers:

chubhunter [2.5K]3 years ago

6 0

Answer:

Explanation:

Usually when an acid reacts with metal, salt and hydrogen are produced. Acid + metal = salt + hydrogen. Example calcium nitrate + hydrogen. Hope this helps

meriva3 years ago

4 0

Answer:

The more reactive the metal, the more rapid the reaction is. A metal below hydrogen in the reactivity series will not react with dilute acids.

Explanation:

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Which is equal to a temperature of 50 degrees F? 18 degrees C, 46 degrees C, 10 degrees C, 32 degrees C?

kakasveta [241]

Answer:

10 degrees C

Explanation:

4 0

3 years ago

How many atoms of N are in 0.82 g of NaNO3? ( molar conversion)

VMariaS [17]

The number of atoms N = 5.8 x 10²¹

<h3>Further explanation</h3>

A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

mass of N in 0.82 g of NaNO₃ (MW NaNO₃: 85 g/mol) :

$\tt mass~N=\dfrac{Ar~N}{MW~NaNO_3}\times mass~NaNO_3\\\\mass~N=\dfrac{14}{85}\times 0.82\\\\mass~N=0.135~g$

moles of N :

$\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{0.135}{14}=0.0096$

The number of atoms N :

$\tt N=n\times No\\\\N=0.0096\times 6.02\times 10^{23}\\\\N=5.8\times 10^{21}~atoms$

4 0

3 years ago

Which of the following elements will gain electrons to form an

blsea [12.9K]

Answer:

Explanation:

When an atom lose or gain electrons ions are formed.

There are two types of ions. Cation and anion.

Cation:

Cations are formed when atom lose electrons. For example:

X → X⁺ + e⁻

Anion:

It is formed when an atom gain electrons. For example:

X + e⁻ → X⁻

Fluorine is present in group seventeen. It has seven valance electrons. It gain one electron to complete the octet and form anion with charge of -1.

Calcium is alkaline earth metal. It is present in group two it loses two valance electrons and form cation with charge of +2.

Neon is noble gas. It already have complete octet. It can not form ions. To remove the electrons from noble gases very high temperature is required.

Zinc is present in group 12. It usually form cation by losing its two valance electrons but it can also show oxidation state -2.

7 0

3 years ago

153 mL of 2.5 M HF is reacted with an excess of Ca(OH)2. How many grams of CaF2 will be produced?

Delvig [45]

Answer:

15 g

Explanation:

Data given:

amount of HF = 153 mL 2.5 M HF

amount of Ca(OH)₂ = Excess

grams of CaF₂ = ?

Reaction Given:

2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

Solution:

First we have to find number of moles of HF in 153 mL of 2.5 M HF

For this we will use following formula

Molarity = moles of solute / liter of solution

Rearrange above equation

moles of solute = Molarity x liter of solution . . . . . (1)

Put values in above equation (1)

moles of solute = 2.5 x 1 L

moles of solute = 2.5

So,

we come to know that there are 2.5 moles of solute (HF) in 1 L of solution

Now how many moles of solute will be present in 153 ml of solution

Convert 153 mL to Liter

1000 mL = 1 L

153 mL = 153/1000 = 0.153 L

Apply Unity Formula

2.5 moles HF ≅ 1 L solution

X moles of HF ≅ 0.153 L solution

moles of HF = 2.5 moles x 0.153 mL solution / 1 L solution

moles of HF = 0.383 moles

So, 153 mL contains 0.383 moles of HF

Now Look at the reaction:

2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

2 mol 1 mol

From the reaction we come to know that 2 moles of HF gives 1 mole of CaF₂ then how many moles of CaF₂ will be produced from o.383 moles of HF

Apply Unity Formula

2 moles HF ≅ 1 mole of CaF₂

0.383 moles of HF ≅ X moles of CaF₂

moles of CaF₂ = 0.383 moles x 1 mole / 2 mol

moles of CaF₂ = 0.192 moles

So, 0.192 moles of CaF₂ will be produced by 0.383 moles of HF

Now we will find mass of 0.192 moles of CaF₂

Formula will be used

mass in grams = no. of moles x molar mass . . . . . . . (2)

molar mass of CaF₂ = 40 + 2(19)

molar mass of CaF₂ = 40 + 38 = 78 g/mol

Put values in eq. 2

mass in grams = 0.192 x 78 g/mol

mass in grams = 14.976 g

rounding the value

mass in grams = 15 g

So,153 mL of 2.5 M HF is reacted with an excess of Ca(OH)₂ will produce 15 g of CaF₂.

6 0

4 years ago

How many grams of KOH are dissolved in 2.50 liters of 1.50 M KOH? (The molar mass of KOH = 56.11 g/mol) 210 grams 93.5 grams 15

romanna [79]

<span>There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We can calculate as follows:

Mass of KOH = 1.50 mol KOH/ L solution (2.50 L) (56.11 g/mol) = 210.41 g KOH

Therefore, the first option is the answer. </span><span />

5 0

3 years ago