Answer:
the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.
Calculate the mass of water used
that is
100-22.2=77.8g convert into Kg = 77.8/1000=0.0778Kg of water
then calculate the moles of HCOOH used
that is 22.2g/molar mass of HCOOH(1+12+16+16+1)=46
therefore the moles of HCOOH=22.2/46=0.48moles
the mole of water= 77.8/18(molar mass of water= 4.32moles
the molarity of HCOOH = 0.48mol/0.0778kg=6.17M
The mole ratio= moles of HCOOH divided by total moles
the total moles= 0.48+4.32=4.8moles
therefore the mole ratio= 0.48/4.8moles=0.1(the moles fraction of HCOOH)
Answer:
a. 50KCal
b. 400KCal
c. Same as (a) above
Explanation:
Given
To raise the temperature of 1kg of liquid water at 1°C requires 1KCal
To raise the temperature of 1kg of ice or water vapour by 1°C requires 0.5KCal
To melt 1kg of ice at 0°C requires 80KCal
To evaporate 1kg of liquid water sitting at 100°C requires 540KCal
a. How much heat is required to raise the temperature of 5 kg of liquid water by 20 C?
To raise the temperature of 5 kg of ice by 20°C requires:
5 kg * (0.5 kcal / kgC) * 20C
= 50 KCal
b. How much heat is required to melt 5 kg of ice at 0 C?
To melt an ice of 5 kg of ice at 0 C requires:
5 kg * (80 kcal / kg)
= 400 KCal
c. Same as (a) above
