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Norma-Jean [14]
2 years ago
10

It’s due in 5 minutes pls help!!..

Chemistry
1 answer:
Monica [59]2 years ago
6 0

Answer:

c

Explanation:

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PLEASE HELP!! thank you Which element does X represent?
jarptica [38.1K]

Answer:

95 Kr36

Explanation:

The process by which a large nucleus split into two smaller nuclei is called nuclear fission and occurs after the nucleus has absorbed a neutron that is a product of the radioactive decay of another atom. The formed fission fragments are unstable and extremely radioactive.

8 0
3 years ago
How many moles are equal to 89.23 g of calcium nitrate?
DanielleElmas [232]

Answer:

23

Explanation:

6 0
3 years ago
A large balloon contains 5400 m3 of He gas that is kept at a temperature of 280 K and an absolute pressure of 1.10 x 105 Pa. Fin
patriot [66]

Answer:

1.02 × 10⁶ g

Explanation:

Step 1: Given data

  • Volume of the balloon (V): 5400 m³
  • Temperature (T): 280 K
  • Absolute pressure (P): 1.10 × 10⁵ Pa
  • Molar mass of He (M): 4.002 g/mol

Step 2: Convert "V" to L

We will use the conversion factor 1 m³ = 1000 L.

5400 m³ × 1000 L/1 m³ = 5.400 × 10⁶ L

Step 3: Convert "P" to atm

We will use the conversion factor 1 atm = 101325 Pa.

1.10 × 10⁵ Pa × 1 atm / 101325 Pa = 1.09 atm

Step 4: Calculate the moles of He (n)

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.09 atm × 5.400 × 10⁶ L / 0.08206 atm.L/mol.K × 280 K

n = 2.56 × 10⁵ mol

Step 5: Calculate the mass of He (m)

We will use the following expression.

m = n × M

m = 2.56 × 10⁵ mol × 4.002 g/mol

m = 1.02 × 10⁶ g

8 0
3 years ago
How do you draw acetone using a Bohr model?
Inessa [10]

Explanation:

this is the one i found.....

6 0
3 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
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