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Norma-Jean [14]
3 years ago
10

It’s due in 5 minutes pls help!!..

Chemistry
1 answer:
Monica [59]3 years ago
6 0

Answer:

c

Explanation:

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Which of the following solutions is a buffer? Which of the following solutions is a buffer? a solution of sulfuric acid and sodi
Sever21 [200]

Answer:

a solution of acetic acid and sodium acetate

Explanation:

A buffer solution is defined as a solution which resist a change in pH when small quantity of a strong acid or a strong base are added. A buffer solution is made up of mixture of a weak acid and its conjugate base or a mixture of a weak base and its conjugate acid.

Acetic acid is the only option because it is a weak acid with a corresponding conjugate base, acetate. Unlike a solution of sulfuric acid and sodium sulfate in which the sulfuric acid is a strong acid which doesn’t qualify it to be a buffer solution. The remaining options have different acid compounds paired together which makes them invalid too.

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3 years ago
Use the diagram to answer Question 3.
Ierofanga [76]

D. The limb bones do not look as developed as

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2 years ago
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Calculate the ionization constant for the following acids or bases from the ionization constant of its conjugate base or conjuga
suter [353]

Answer:

7.41 × 10⁻⁵

Explanation:

Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).

(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻

According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.

pKa + pKb = 14

pKa = 14 - pKb = 14 - 9.87 = 4.13

Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.

pKa = -log Ka

Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵

8 0
3 years ago
Iodide (KI). Identify the correct products of this
TEA [102]

Answer:

AgNO3 + KI → Agl + KNO3. Double-replacement reaction

Explanation:

Based on solubility rules, Silver, Ag produce an insoluble salt in presence of halides (Fluorides F-, Chlorides Cl-, Iodides, I-, and bromides Br-). That means the mixture of AgNO3 (Ag⁺ ions) with KI (I- ions) produce AgI as insoluble salt.

The reaction is:

<h3>AgNO3 + KI → Agl + KNO3</h3><h3 />

And this is a double-replacement reaction where the cations exchange of anion to produce 2 new compounds.

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3 years ago
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How many moles of copper would be produced by reacting 34.0 grams of iron with copper(II) chloride solution?
Jlenok [28]
13.6 mol of CuCl2
 you wanna use the factor label 

5 0
3 years ago
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