Answer:
a. AB: 3 by 7
b. BA: N by N
c. A^TB: N by N
d. BC: 6 by 3
Step-by-step explanation:
Given
Required
The dimension of the following matrices
As a general rule:
For A * B to be successful, the columns in a must equal the rows in B
Using this rule, we have:
So:
The column numbers of B does not equal the row numbers of A.
Hence, BA does not exist
implies that:
If , then
So:
The column numbers of A^T does not equal the row numbers of B.
Hence, 
does not exist
Answer:
Two solutions (-4,-7) and (4,7)
Step-by-step explanation:
x = y + 3
x*y = 28
(y+3)*y=28
y^2+3y-28=0
(y+7)(y-4)=0
y=-7, y=4
x=-4, x=7
1. =4/16 which in simplified terms = 1/4
2. = 37/99 (find the lowest common denominator which is 99 then multiply them, then combine fractions then subtract them)
3. 2/25
4. 12/18 which simplified is 2/3
5. 5/15 which simplified = 1/3
Hope you understand that:)
Well basically you just have to chose a number of sides for the side length of the square to be and move those many places to get another vertex of the square. For example if we have (-2,3) and we choose the side lengths to be 4 units than you could move 4 places up, down, left, or right to get the other vertices for the square
Hope that helps :)
N+8>11 is the answer you are looking for
