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(8+12) > side > |8-12|
20 > side > 4, Then 4 cm is the solution.
Whit a triangle solver: http://triancal.esy.es/?a=8&b=12
20 > side > 4, Then 4 cm is the solution.
Whit a triangle solver: http://triancal.esy.es/?a=8&b=12
Answer:3872
Step-by-step explanation: If base length and base width equal 22, and pyramid height is 24 then you multiply those and divide by three.
V=
Answer:
97.27 yd²
Step-by-step explanation:
First let's find the area of the right triangle on the left side. To do that, multiply 6x5, then divide the product by 2, since a right triangle is half a rectangle.
6x5=30
30/2=15
Area of triangle=15 yd²
Find area of the middle rectangle. So multiply the length by the width.
9x6=54
Area of rectangle=54 yd²
Find area of the half circle. Formula for area of circle is . Pi is about 3.14, and radius (
) is 3. Radius is half of the diameter of circle, and the 6 on the left says the diameter of circle.
x
≈28.27
Area of circle is about 28.27 yd²
Add up the three areas.
15+54+28.27=97.27
Answer:
(3, 13)
Step-by-step explanation:
i plugged the two lines into desmos :)
