The third angle should be 83.
90+7+83=180
Answer:
The Prime Factorization is:
2 x 7
In Exponential Form:
21 x 71
CSV Format:
2, 7
Prime Factors Tree
14
/ \
2 7
Prime[1] = 2, Prime[4] = 7
Step-by-step explanation:
Answer: a) 4, b) 13 and c) 17
Step-by-step explanation:
Since we have given that
Number of elements in A = 9
Number of elements in B = 4
a) What is the largest possible value for A∩B.
Since B has only 4 elements.
So, As largest possible, it can be B⊆A.
So, Largest possible value for A∩B = 4
(b) What is the largest possible value for AUB?
If suppose A∩B = Ф
n(A∩B) = 0
So, it becomes,
![n(A\cup B)=n(A)+n(B)-n(A\cap B)\\\\n(A\cup B)=9+4-0\\\\n(A\cup B)=13](https://tex.z-dn.net/?f=n%28A%5Ccup%20B%29%3Dn%28A%29%2Bn%28B%29-n%28A%5Ccap%20B%29%5C%5C%5C%5Cn%28A%5Ccup%20B%29%3D9%2B4-0%5C%5C%5C%5Cn%28A%5Ccup%20B%29%3D13)
So, the largest possible value for A∪B = 13
(c) What is the value of AU B+A∩B?
|A∪B|+|A∩B|=13+4=17
Hence, a) 4, b) 13 and c) 17
Answer:
B) 6.9 cm
Step-by-step explanation:
The remaining angle is the smallest, 180° -48° -97° = 35°. The shortest side is opposite this angle. The Law of Sines tells you its length is ...
short side = (longest side)·(sin(smallest angle)/sin(largest angle))
= (12 cm)sin(35°)/sin(97°) ≈ 6.9 cm
The shortest side is about 6.9 cm.
Answer:
see below for the graph
Step-by-step explanation:
The desired graph has two y-intercepts and one x-intercept. It is not the graph of a function.
Here's one way to get there.
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Start with the parent function y = |x| and scale it down so that it has a y-intercept of -1 and x-intercepts at ±1.
Now, it is ...
f(x) = |x| -1
We want to scale this vertically by a factor of -5. this puts the y-intercept at +5 and leaves the x-intercepts at ±1.
Horizontally, we want to scale the function by an expansion factor of 3. The transformed function g(x) will be ...
g(x) = -5f(x/3) = -5(|x/3| -1) = -5/3|x| +5
This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want:
x = -(5/3)|y| +5
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<em>Comment on this answer</em>
Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. It need not be describable by an equation.