Answer:
hey i know this might not help the way you want it to but try using khan Academy these videos might be helpful
Step-by-step explanation:
Here;
Y=(3×22)/11. [ By Cross Multiply]
Y=66/11
:Y=6
May be Helpful.
Thank You
Answer:
![\displaystyle 4\sqrt[7]{x^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%5Csqrt%5B7%5D%7Bx%5E3%7D)
General Formulas and Concepts:
<u>Algebra I</u>
- Exponential Rule [Root Rewrite]:
![\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Rewrite</u>
- Split:

- Rewrite [Exponential Rule - Root Rewrite]:
![\displaystyle 4\sqrt[7]{x^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%5Csqrt%5B7%5D%7Bx%5E3%7D)
Answer:
Angle CBA
Step-by-step explanation:
It would be CBA because Angle 1 is between those 3 points. Angle 1 is where B is so B would have to go in the middle.
Hope this helps :)
Divide by 7.
... |-7x -3| = 3
Unfold to two equations.
... -3 = -7x -3 . . . . . the content of the absolute value is negative
... 0 = -7x . . . . . . . . add 3
... 0 = x . . . . . . . . . . divide by -7
and
... 3 = -7x -3 . . . . . . the content of the absolute value is positive
... 6 = -7x . . . . . . . . add 3
... -6/7 = x . . . . . . . . divide by -7
The solutions are ...
... x = -6/7 or x = 0
_____
Many graphing programs will happily tell you the locations of x- and y-intercepts, so it is convenient to rewrite the equation so its value is zero at the solution points. We can do that by subtracting the right side constant to get ...
... 7|-7x -3| -21 = 0