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ivanzaharov [21]

4 years ago

6

0.9 X 2.8 help me asap you get barinist

1 answer:

tia_tia [17]4 years ago

8 0

Answer:

2.52

Step-by-step explanation:

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vredina [299]

Answer:

Step-by-step explanation:

6 0

3 years ago

Sebastian rides his bike 2000 meters in 5 minutes. How many meters does he bike in 1 minute

kherson [118]

The answer is 4 have a nice

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3 years ago

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7c??? help on 7c???? please?!

Salsk061 [2.6K]

It would be a 12.5% increase. First you find her monthly wages: $10.50 x 160 hours= $1680 a month. Her insurance is $210/month. So you need to find what percentage 210 is of 1680. So $1680*x=210$ . Solve for x by dividing 1680 on both sides and you get 0.125. Multiply by 100 to get the percentage and you get 12.5%. Check your answer by multiplying 1680 x 0.125 and you get 210.

6 0

3 years ago

Josh orders 12 soccer jerseys for his team, including his coach. He pays a total

posledela

Answer:

4955

Step-by-step explanation:

soccer jerseys--> 12

total--> R 59460

= 59460 divided by 12

= 4955

Ans: Each jersey costs R 4955.

thenks and mark me brainliestt pls :))

3 0

3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

or

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago