To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that

and the exponent

are divisible by index

. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is:
Part 1:
6(x-5) = 5(x+5) (x = 55)
4y + 2 (-3 + 2y) = 1-y (x = 7/9)
Part 2:
4(a-6) = 8a - (4a-24) (No Solution)
4(2x-8) = 8(x-8) (No Solution)
2(3x-3) = -6x-6 (Identity (x = 0))
Answer:
97.3 and 37.4 hope i helped
Step-by-step explanation:
3-4 = -1
Hope this helps!
:)
Answer:
MJK & PJR = Unequal
LJP & NJR = Equal
KJR & MJP = Equal ? (not too sure with this one)
MJP & PJR = Unequal
KJL & LJM = Unequal