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AlekseyPX
3 years ago
10

Polygon ABCD goes through a sequence of rigid transformations to form polygon A′B′C′D′. The sequence of transformations involved

is a reflection across the ___ , followed by a reflection across the line ___.

Mathematics
2 answers:
Kaylis [27]3 years ago
7 0

Answer:

<h2>y = x line</h2><h2>x = 0 line</h2>

Step-by-step explanation:

The polygon ABCD showed in the image attached is first reflected across the y = x line, from the second quadrant to the fourth quadrant. This reflection will result like the second image.

Then, it's reflect across the y-axis, which in terms of lines would be x = 0 line. This reflection will be like the last position showed in the first image, it's a common reflection with y-axis as a mirror.

Sever21 [200]3 years ago
5 0
Polygon ABCD goes through a sequence of rigid transformations to form polygon A′B′C′D′. The sequence of transformations involved is a reflection across the _Y-axis _, followed by a reflection across the line _y=-x__.
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Paul [167]

Answer:

Step-by-step explanation:

I'm guessing we are missing a piece of the question such as the average speed at which Nadeem can ride. Let's call it v

distance is a product of velocity and time

d = vt

t = d/v

so if v is in miles/hr, an inequality could be

12/v ≤ t ≤ 15/v

5 0
3 years ago
Find the distance from point A to the given line:<br> A(-1, 7), y=3x<br><br> How do I solve this?
kipiarov [429]

he formula of a distance between a point (a, b)

and a line Ax + By + C = 0:

d=\dfrac{|Aa+Bb+C|}{\sqrt{A^2+B^2}}

We have the point A(-1, 7) → a = -1, b = 7

and the line y = 3x → 3x - y = 0 → A = 3, B = -1, C = 0.

Substitute:

d=\dfrac{|(3)(-1)+(-1)(7)+0|}{\sqrt{3^2+(-1)^2}}=\dfrac{|-3-7|}{\sqrt{9+1}}=\dfrac{|-10|}{\sqrt{10}}=\dfrac{10\sqrt{10}}{\sqrt{10}\cdot\sqrt{10}}\\\\=\dfrac{10\sqrt{10}}{10}=\sqrt{10}

<h3>Answer: d = √10</h3>
3 0
3 years ago
What is the difference between a $20,000 and a $30,000 annual salary over a lifetime
Lelu [443]
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7 0
4 years ago
Next
AveGali [126]

Answer:

C. Robbie's glider

Step-by-step explanation:

P.S -The exact question is -

Given - Melissa and Robbie are flying remote control gliders.

The altitude of Melissa's glider, h(s), in feet, is modeled by this function, where sis time, in seconds, after launch.

m(s) = 0.4(s³ - 11s² + 31s – 1)

The altitude of Robbie's glider is modeled by function r, where sis time, in seconds, after launch.

To find - Which glider reaches the greater maximum altitude in the first 6 seconds after launch?

A. Neither glider reaches a maximum altitude on the given interval.

В. Melissa's glider

C. Robbie's glider

D. Both gliders reach the same altitude on the given interval.

Proof -

At t = 6 sec,

Melisa glider is

h(6) = 0.4((0.6)³ - 11(0.6)² + 31(0.6) – 1)

      = 0.4( 0.216 - 3.96 + 18.6 - 1 )

      = 0.4(13.856) = 5.5424

⇒h(6) = 5.5424

∴ we get

At t = 6 seconds, Melissa glider is at the altitude of 5.54 feet

Now,

From the figure, we can see that,

At t = 6 seconds, Robbie's glider is approximately at an altitude of 13 feet

Now,

As 13 > 5.5

So,

Robbie's glider is at maximum height in 6 seconds after the launch.

So,

The correct option is - C. Robbie's glider

8 0
3 years ago
1<br> Find the value of the variables.<br> b<br> 30°<br> a<br> 12<br> 60°<br> a-<br> b =
Andrew [12]

Answer:

a=6

b=10.39

Step-by-step explanation:

a=sin 30x12 or a=cos60x12

a=6

b=cos 30x12 or b=sin60x12

b=10.39

4 0
3 years ago
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