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3 years ago

I need help with these questions :(see image)

Physics

2 answers:

Artist 52 [7]3 years ago

5 0

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>

Initial velocity = $V_0 = 50\frac{m}{s}$

Height = H = 100 m

Acceleration due to gravity = g = 10 m/s^2

Time of flight = ?

Angle of projection= θ(theta) = ?

Range attained = ?

A) The Relation between Height and Total time of flight is given by,

$T = 2(\sqrt\frac{2H}{g})\\\\T = 2( \sqrt\frac{2x100}{10})\\\\T = 2(\sqrt\frac{200}{10})\\\\T = 2(4.47)\\\\T = 8.94 seconds$

B) Total time of flight is given by,

$H = \frac{V_0^2Sin^2(theta)}{2g}\\\\100 x2x10 = 50^2Sin^2(theta)\\\\2000 = 2500Sin^2(theta)\\\\\frac{2000}{2500} = Sin^2(theta)\\\\Sin^2(theta)= \frac{4}{5}\\\\$

Square root on both sides,

$Sin(theta) = \frac{2}{\sqrt{5}}\\\\theta = Sin^{-1}(\frac{2}{\sqrt{5} })\\\\theta = 63.4 degrees$

C) The range attained is given by,

$R = \frac{V_0^2}{g} xSin2(theta)\\\\R = \frac{50^2}{10} x Sin(2x63.4)\\\\R = 250 x 0.8\\\\R = 200meters$

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz' </h2><h2 />

Levart [38]3 years ago

3 0

Answer:

I think it's letter b.

correct me if my answer is wrong.

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I need help with these questions :(see image)​

I need help with these questions :(see image)