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Svetach [21]
3 years ago
7

What increases your ability to see at night

Physics
1 answer:
PtichkaEL [24]3 years ago
8 0
The answer would be increased number <span />of rod cells.Hope this helps :)


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A ford escort needs a force of 3500N to accelerate at the rate of 4.9 m/s2. What is the mass of the car?
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714 kg

Explanation:

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3500N = 4.9m/s^2*m

m ~= 714 kg

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What is the relationship between distance, time and acceleration
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4 years ago
What are some ways in which the temperature of a substance can be measured
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The three most normal units of estimation for temperature are Celsius, Fahrenheit, and Kelvin.

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3 0
2 years ago
Two point charges of equal magnitude (and opposite sign) are 7.5 cm apart. At the midpoint of the line connecting them, their co
Shkiper50 [21]

Comment

The only reason you can do this is that the charges are the same. If they were not, the problem would not be possible.

Equation

The field equation is, in its simplest form,

E = kq/r^2

So each of the charges are pulling / pushing in the same direction. The equation becomes.

kq/r^2 - (-kq/r^2) = Field magnitude in N/C

Givens

  • K = 9 * 10^9 N m^2 / c^2
  • E = 45 N/C
  • r = 7.5/2 = 3.75 cm * ( 1 m / 100 cm) = 0.0375 m
  • Find Q

Solution

k*q/0.0375 ^2 - (-kq/0.0375^2) = 45 N/C           Combine

2*k*q / 0.0375^2 = 45 N/C                                  Divide by 2

kq /(0.0375^2) = 22.5 N/C                                   Multiply by 0.0375^2

kq = 22.5 * 0.0375 ^2                                           Find d^2

kq = 22.5 * 0.001406                                            Combine

kq = 0.03164 N/C * m^2                                        Divide by k

q = 0.03164 N * m^2 /C / 9*10^9 N m^2 / c^2

q = 2.84760 * 10 ^8 C

I've left the cancellation of the units for you. Notice that only 1 C is left and it is in the numerator as it should be.


7 0
4 years ago
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