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zhenek [66]
3 years ago
15

PLEASE HELP I AM GIVINF 99 POINTS PLEASE

Physics
1 answer:
dybincka [34]3 years ago
6 0

Answer:

B

Explanation:

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The power rating of a light bulb (such as a 100-W bulb) is the power it dissipates when connected across a 120-V potential diffe
bazaltina [42]

To solve this problem we will apply the concepts related to the calculation of power, from the two electrical forms:

P = VI

P = \frac{V^2}{R}

Here,

V = Voltage

I = Current

R= Resistance

P = Power

PART A)

R = \frac{V^2}{P}

Replacing,

R = \frac{(120V)^2}{150W}

R = 96\Omega

Resistance of bulb is 96\Omega

PART B)

I = \frac{P}{V}

I = \frac{150W}{120V}

I = 1.25A

The bulb will draw 1.25A current

7 0
3 years ago
Which option below correctly compares the average annual dose of background radiation to the dose liked to an increased cancer r
julia-pushkina [17]
The answer for this question would be choice "<span>B. The average annual dose of background radiation is 250 times smaller than the dose linked to increased cancer risk."

You only have to compare 4.0 x 10^-4 and 1.0 x 10^-1. And if you can observe carefully, when you try to multiply the average annual dose of background radiation by 250, you would get 0.1 which is equivalent to the amount of annual dose linked to increased cancer risk. Therefore, the answer is B.</span>
6 0
3 years ago
Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​
Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ )}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ )}{9.8}}

d=35.35\ m

The range is 35.35 m

7 0
3 years ago
A projectile was launched horizontally with a velocity of 388 m/s, 2.89 m above the ground. How long did it take the projectile
tamaranim1 [39]

Answer:

Explanation:

Given

Velocity = 388m/s

Height S = 2.89m

Required

Time

Using the equation of motion

S =ut+1/2gt²

2.89 = 388t+1/2(9.8)t²

2.89 = 388t+4.9t²

Rearrange

4.9t²+388t-2.89 =0

Factorize

t = -388±√388²-4(4.9)(2.89)/2(4.9)

t= -388±√(388²-56.644)/9.8

t = -388±387.93/9.8

t =0.073/9.8

t = 0.00744 seconds

6 0
3 years ago
What type of quantity is specified by direction and magnitude?
Kaylis [27]

Answer:

A vector is any quantity with both magnitude and direction. Other examples of vectors include a velocity of 90 km/h east and a force of 500 newtons straight down.

Explanation:

7 0
4 years ago
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