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cricket20 [7]
3 years ago
5

An element from group 2 on the periodic table will bond lonically with elements from group 17(7A)

Physics
1 answer:
Natalija [7]3 years ago
8 0

Answer:

Elements in group IIA have 2 electrons in their outermost shell so they can donate these electrons of group VII A which have seven electrons in their outermost shell. So it is necessary 2 elements of group VII A, each atoms accepts one electron.

Explanation:

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Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. Each elevator has a mass of 1,00
wlad13 [49]

Answer:

Power output = 2\times 10^4\ W

Explanation:

Given:

Mass of the elevator is, m=1000\ kg

Height to which it is raised is, h=10\ m

Acceleration due to gravity is, g=10\ m/s^2(Approximately)

Time taken by the motor to raise the elevator is, t=5.0\ s

Now, work done on the elevator by the motor is equal to the increase in the gravitational potential energy of the elevator.

Increase in gravitational potential energy is given as:

\Delta U=mgh=(1000)(10)(10)=10\times 10^4\ J

Therefore, work done by motor is, W=10\times 10^4\ J

Now, we know that, power is work done in unit time. So, power output is given as:

Power=\frac{W}{t}\\\\Power=\frac{10\times 10^4\ J}{5.0\ s}\\\\Power=2\times 10^4\ J/s\\\\Power=2\times 10^4\ W..........[1 W = 1\ J/s]

Therefore, the power output of the first motor is 2\times 10^4\ W

7 0
3 years ago
6.3 Calculate the current that flows through the element of a heater when the potential difference is 250V and the resistance of
ryzh [129]

Answer:

16.66

Explanation:

3 0
2 years ago
explain the fleming left-hand rule with the diagram and what will the direction of the induced current in the figure if the magn
iVinArrow [24]
Hi sorry

I don’t know

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4 0
2 years ago
A bike moves. 50 m in 10 seconds calculate the speed of the bike
vagabundo [1.1K]

Answer:

We know that

Speed = Distance/ Time

Explanation:

  • Distance is 50 m
  • Time is 10 seconds

Speed = 50/10

= 5 m/s

5 0
3 years ago
A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent
azamat

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

  • <em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

5 0
3 years ago
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