It depends on how this is done. If you raise the pressure, the nitrogen will disappear (liquify) and all that will be left will be the 21 % oxygen and the 1% argon.

The process is very complicated because the boiling point of nitrogen keeps on changing. The boiling point is unstable.

6 0

3 years ago

5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?

Margaret [11]

Answer:

$\boxed {\boxed {\sf 2.8 \ m }}$

Explanation:

The formula for molality is:

$m=\frac{moles \ of \ solute}{kg \ of \ solvent}$

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

$moles= 0.210 \ mol \\kilograms = 0.075 \ kg$

Substitute the values into the formula.

$m= \frac{ 0.210 \ mol }{0.075 \ kg}$

Divide.

$m= 2.8 \ mol/kg= 2.8 \ m$

The molality is <u>2.8 moles per kilogram</u>

5 0

3 years ago

13.0 g NaHSO4 is dissolved in water to make a 2.00 L solution what is the molarité

Sati [7]

Answer:

0.054 M

Explanation:

1 mol NaHSO4 -> 120 g

x ->13 g

x= 0.108 mol NaHSO4

M= mol solute/ L solution

M= 0.108 mol NaHSO4/ 2.00L

M= 0.054 M

8 0

3 years ago

Hi! My responsibility is to add and protection to plant cells. what i am

liq [111]

Probably a cell wall

4 0

3 years ago