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4 years ago

What is the charge of a magnesium ion?

Chemistry

2 answers:

kupik [55]4 years ago

7 0

2+ charge electrons of course

Leokris [45]4 years ago

7 0

Answer:

Magnesium will remain positively charged +2 → Mg⁺²

Explanation:

The octet rule states that the atoms of the elements bind each other in the attempt to complete their valence shell with eight electrons. That is to say, the atoms will tend to yield or share electrons to complete eight electrons in the valence layer through an ionic, covalent or metallic bond.

In other words, the objective is to have the closest noble gas electronic configuration, thus having the last complete electron layer and acquiring stability.

This defines the electronic tendencies of each atom, being able to yield (and we call these cations) or tendency to accept (and we call them anions).

In the case of Mg, this element is closer to Ne (Neon) and will tend to lose the last two electrons and thus, its electronic configuration would be the same. In this way, since electrons are negative, Magnesium, by transferring its electrons, will remain positively charged +2 → Mg⁺²

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What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5

djyliett [7]

Question:

What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5 hydroxyl group?

a. disaccharide

b. carboxylic acid

c. hemiacetal

d. ester

e. stereoisomer

Answer:

hemiacetal forms in the intramolecular reaction between the aldehyde portion of the glucose molecule and its C-5 hydroxyl group

Explanation:

It is an alcohol also an ether that has been attached to the carbon molecule. Here the hydrogen has occupied the fourth bonding position. This hemiacetal has been derived from the aldehyde. Hence, hemiketal being an alcohol as well as ether has been attached to the same carbon and also to the two other carbon.

7 0

3 years ago

If there are 7.2 mol of H, how many moles of each do the following compounds are present? H2SO4

serg [7]

7.2 mol H × (1 mol H_2SO_4/2 mol H) = 3.6 mol H_2SO_4

8 0

3 years ago

Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the pipi

Ugo [173]

Answer:

-3.617 °C

Explanation:

Step 1: Given data

Mass of water (m): 210.0 g

Energy released in the form of heat (Q): -3178 J (the minus sign corresponds to energy being released)

Specific heat of water (c): 4.184 J/g.°C

Temperature change (ΔT): ?

Step 2: Calculate the temperature change

We will use the following expression.

Q = c × m × ΔT

-3178 J = 4.184 J/g.°C × 210.0 g × ΔT

ΔT = -3.617 °C

6 0

3 years ago

The two isotopes of chlorine are 35/17 cl and 37/17cl. which isotope is the most abundant

Natalka [10]

The most abundant is 35/17 Cl

explanation

This is because Chlorine 35/17 is the one close to the average atomic mass of chlorine which is 35.46 u making it to be the most abundant.

average atomic mass of chlorine is 35.46 + or- 0.02

7 0

3 years ago

Calculate the volume of 1.0 x 10-4 M CV+ solution that needs to be added to a 25.0 mL volumetric flask and diluted with deionize

xenn [34]

Answer:

The answers are: 2.5 ml (first part) and 3.0 ml (second part)

Explanation:

In order to calculate volumes required to prepare diluted solutions we use the following equation:

Vc x Cc = Vd x Cd

Where Vc and Cc are the volume and concentration respectively of concentrated solution (higher concentration) whereas Vd and Cd are volume and concentration of diluted solution (lower concentration).

In both problems we want to prepare a diluted solution and we know the final concentration (Cd) and final volume (Vd) and the initial concentration (Cc).

In first part, we have: Cc= 1.0 10⁻⁴ M; Vd= 25 ml; Cd= 1.0 10⁻⁵ M

Vc= Vd x Cd / Cc= (25 ml x 1.0 10⁻⁵ M)/1.0 10⁻⁴ M = 2.5 ml

Notice that Cc/Cd= 1.0 10⁻⁴ M/Cd= 1.0 10⁻⁵ M= 10 (so, we have to dilute the solution 10 times, and for this we have to take a volume 10 times lower than the final volume).

To prepare the solution, we take 2.5 ml of 1.0 10⁻⁵ M CV+, we dispense the volume in a 25 ml volumetric flask and then we add water until complete 25 ml (aproximately 22.5 ml of water).

In the second part is the same. We have: Vd= 10 ml; Cc= 1.0 10⁻⁴M; Cd= 3.0 10⁻⁵M.

Vc= Vd x Cd / Cc= (10 ml x 3.0 10⁻⁵ M)/1.0 10⁻⁴ M = 3 ml

To prepare the solution, we take 3 ml of 3.0 10⁻⁵ M CV+, we dispense the volume in a 10 ml volumetric flask and then we add water until we complete 10 ml (aproximately 7 ml of water).

6 0

3 years ago