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Marrrta [24]
3 years ago
11

Plsss help ASAP!!! BRAINLIEST

Chemistry
2 answers:
likoan [24]3 years ago
8 0

Answer:

-175.15

Explanation:

1.0 °C = 274.15 K

2.0 °C = 275.15 K

3.0 °C = 276.15 K

4.0 °C = 277.15 K

5.0 °C = 278.15 K

6.0 °C = 279.15 K

7.0 °C = 280.15 K

8.0 °C = 281.15 K

9.0 °C = 282.15 K

Harrizon [31]3 years ago
3 0
371.7 k hope this helps
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Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH
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Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

    No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{12 g}{60 g/mol}

                           = 0.2 mol

Molarity of acetic acid is calculated as follows.

              Density = \frac{mass}{volume}

                 1 g/ml = \frac{100 g}{volume}

                    volume = 100 ml

Hence, molarity = \frac{\text{no. of moles}}{volume}

                           = \frac{0.2 mol}{0.1 L}

                           = 2 mol/l

As reaction equation for the given reaction is as follows.

     NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O

So,          moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

          x \times 1 M = 10 mL \times 2 M     (as 1 L = 1000 ml)

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Thus, we can conclude that volume of NaOH required is 20 ml.                    

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