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VladimirAG [237]
3 years ago
5

what is the region surrounding the nucleus which is occupied by electrons?????? its a crossword ( _ _ _ _ _ _ _ _ C _ _ _ _)

Chemistry
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

Electron cloud

Explanation:

The electron cloud is an informal term in chemistry and physics. This region describes the negatively charged electrons in their orbit surrounding the nucleus in an atom. The nucleus has protons in it that have a positive charge on it. It is not easy to know where exactly an electron in any specific time but the electron cloud helps to know electron is moving in this specific area.

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A factor that keeps a population size from growing too large is called a ______ _______.
Liula [17]

Answer:

limiting factor i think

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What type of electrons are involved in chemical reactions?
sweet-ann [11.9K]

The outermost energy shell of an atom

because they are involved in forming bonds

7 0
3 years ago
If 60 grams of a liquid takes up 120ml how dense is the liquid
Black_prince [1.1K]

Answer:

<h2>Density = 0.5 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

From the question

mass = 60 g

volume = 120 mL

Substitute the values into the above formula and solve

That's

<h3>Density =  \frac{60}{120}  \\  =  \frac{1}{2}</h3>

We have the final answer as

<h3>Density = 0.5 g/mL</h3>

Hope this helps you

4 0
3 years ago
Why is enthalpy important?
belka [17]
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7 0
3 years ago
An equimolar mixture of acetone and ethanol is fed to an evacuated vessel and allowedto come to equilibrium at 65°C and 1.00 atm
frutty [35]

The question is incomplete, the table of the question is given below

Answer:

I) xA= 0.34, yA= 0.55

ii) 76.2 mole % vapor

iii) Percentage of vapor volume = 98%

Explanation:

i) xA= 0.34, yA= 0.55

 xA= 0.34, yA= 0.55

ii)      0.50 = 0.55 nv + 0.34 nL

     Therefore, nV =    0.762 mol vapor and nL = 0.238 mol liquid

This shows 76.2 mole % vapor

iii)  ρA= 0.791 g/cm3 and,  ρE = 0.789 g/cm3

Therefore, ρ = 0.790 g/cm3

Now, we have:

MA = 58.08 g/mol and ME= 46.07 g/mol

So Ml = (0.34 x 58.08)+[(1 -0.34) x 46.07] = 50.15 g/mol

1 mol liquid = (0.762 mol vapor/0.238 mol liquid) = 3.2 mol vapor

Liquid volume = Vl= [1 mol x (50.15 g/mol)] / (0.790 g/cm3) = 63.48 cm3

Vapour volume = Vv = 3.2 mol x(22400 cm3/mol) x [(65+273)/273] = 88747 cm3

Therefore, percentage of vapour volume = 88747 / (88747+63.48) = 99.9 %

3 0
3 years ago
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