Answer:
Sort the lab chemicals in alphabetical order for quick access.
Become familiar with the chemicals to be used, including exposure or spill hazards.
Locate the spill kits and understand how they are used.
Explanation:
There are many chemicals in a laboratory hence they should be sorted out and arranged in alphabetical order so that theory can easily be identified and located whenever they are required.
The properties of each chemical should be known especially hazards connected to exposure or spill of the chemicals.
The students should also familiarize themselves with the contents of spill kits and how they are used.
The fact that there are definite energy levels in the radiation spectra is known since light wavelength has been linked with the energy quantum (Einstein 1905 - Δ=ℎ.). These energy differences explain the reason why the spectrum of atoms is discontinuous (formed by spectral lines).
Bohr had the idea to link it to a change in the orbit radius of the electron around the nucleus (The idea that H atom could be formed by the association of one proton and one electron had been suggested a couple of years before by E. Rutherford).
This outstanding idea was perfected by a whole series of remarquable physicists in the years 1920–1930. It even continues to be refined to this day, where it forms the basis of atomic spectroscopy.
Respuesta:
Yes.
Explicación:
Las teorías se pueden mejorar o modificar a medida que se recopila más información para que la precisión de la predicción sea mayor con el tiempo.
To find the freezing point, you use the following formula
fp solution= fp solvent - Δfp solution
fp solvent= 0 C (since the solvent was not stated, you can assume is water which freezing point is 0 degree celsius)
but first, we need to find the depression in freezing point (Δfp solution)
Δfp solution= Kf x i x m, where Kf is constant for the solvent, i is the number of particles produced by the solute and m is the molality of the solution.
Kf= 1.86 for water
i= 4 , becausethe solute breaks into 4 ions, K3PO4---> 3K+ + PO4-3
m= 2.60
Δfp solution= (1.86) (4) (2.60)= 19.3 C
fp solution= 0 - 19.3C=<span> -19.3C
</span>
for boiling point, we use a similar formula and way to solve it.
Δbp solution= bp solvent + Δbp solution
bp solvent= 100 C for water
to find the elevation boiling point (Δbp soln) is equal to:
Δbp solution= Kb x i x m
Kb= 0.512
i= 4
m= 2.60
Δbp solution= (0.512) (4) (2.60)= 5.32 C
bp solution= 100C + 5.32C= <span>105.32 C</span>
