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3 years ago

Why can't an atom lose or gain a proton?

Chemistry

1 answer:

Lynna [10]3 years ago

3 0

When an atom loses or gains a proton the atomic number is changed making it change what element it is.

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Pls help asap!! plssss

kvv77 [185]

AgNO₃+NaCl⇒AgCl+NaNO₃

<h3>Further explanation</h3>

Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

Reaction

AB + CD⇒AD + CB

So for the option :

1. synthesis/combination reaction

2. decomposition reaction

3. double replacement reaction

4. single replacement reaction

4 0

3 years ago

An -ate or -ite at the end of a compound name ususally indiates that the compound contains...

Zarrin [17]

Answer: Oxygen.

Explanation: The -ate is used for the ion that has the largest number of Oxygen atoms. The -ite would be used for the ion with the smaller amount of oxygen atoms.

4 0

3 years ago

Mrs. Dodge's class is studying minerals. Mrs. Dodge wants her class to complete a test to find out the color of minerals found i

hram777 [196]

Answer:

C) Streak Test

Explanation:

7 0

3 years ago

Determine the empirical formula of a compound containing 48.38 grams of carbon, 6.74 grams of hydrogen, and 53.5 grams of oxygen

Darya [45]

Answer: The empirical formula of the compound becomes $CH_2O$

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

We are given:

Mass of C = 48.38 g

Mass of H = 6.74 g

Mass of O = 53.5 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of C}=\frac{48.38g}{12g/mol}=3.023 mol$

$\text{Moles of H}=\frac{6.74g}{1g/mol}=6.74 mol$

$\text{Moles of O}=\frac{53.5g}{1g/mol}=3.34 mol$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 3.023 moles

$\text{Mole fraction of C}=\frac{3.023}{3.023}=1$

$\text{Mole fraction of H}=\frac{6.74}{3.023}=2.23\approx 2$

$\text{Mole fraction of O}=\frac{3.34}{3.023}=1.105\approx 1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 2 : 1

Hence, the empirical formula of the compound becomes $CH_2O$

5 0

3 years ago

How do you know the difference between a compound and mixture?

lorasvet [3.4K]

Answer:

A compound can only be seperated through chemical means while a mixture are formed when two substances are added together without chemical bonds being formed.

Explanation:

3 0

3 years ago