1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
docker41 [41]
3 years ago
15

What atoms make up one molecule of water?

Chemistry
2 answers:
Ivahew [28]3 years ago
6 0

Answer:

A

Explanation:

2 Hydrogen and 1 Oxygene atoms :D

lisov135 [29]3 years ago
5 0

Answer:

A

Explanation:

You might be interested in
A runner stood at the 100-meter mark on a track. When the timer started, the runner sprinted north to the 200-meter mark. It too
Olegator [25]

Answer:

8 m/s north

Explanation:

3 0
3 years ago
Read 2 more answers
If 16.29 grams of Na2SO4 is mixed with 3.697 grams of C and allowed to react according to the balanced equation: Na2SO4(aq) + 4
abruzzese [7]

<u>Answer:</u> The limiting reagent in the given chemical reaction is carbon metal.

<u>Explanation:</u>

Excess reagent is defined as the reagent which is present in large amount in a chemical reaction.

Limiting reagent is defined as the reagent which is present in small amount in a chemical reaction. Formation of product depends on the limiting reagent.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For sodium sulfate:</u>

Given mass of sodium sulfate = 16.29 g

Molar mass of sodium sulfate = 142 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium sulfate}=\frac{16.29g}{142g/mol}=0.115mol

  • <u>For carbon:</u>

Given mass of carbon = 3.697 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{3.697g}{12g/mol}=0.31mol

For the given chemical reaction:

Na_2SO_4(aq.)+4C(s)\rightarrow Na_2S(s)+4CO(g)

By Stoichiometry of the reaction:

4 moles of carbon reacts with 1 mole of sodium sulfate

So, 0.31 moles of carbon will react with = \frac{1}{4}\times 0.31=0.0775mol of sodium sulfate

As, given amount of sodium sulfate is more than the required amount. So, it is considered as an excess reagent.

Thus, carbon metal is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent in the given chemical reaction is carbon metal.

4 0
3 years ago
Solve for x 5 to the power 2 x + 4 - 25 to the power x - 1 is equals to ​
Dafna11 [192]

Answer:

[][][][][][][][][][][][][][]

4 0
3 years ago
Read 2 more answers
Ayyyyyy<br> todays my birthday<br> hmu plzzz
SVEN [57.7K]

Answer:

happy bday

Explanation:

plz give this brainliest ;)

3 0
3 years ago
Copy and balance these chemical equstions​
lyudmila [28]

where are equations dear????

4 0
3 years ago
Read 2 more answers
Other questions:
  • What is the molar mass of Fe(NO3)3
    5·1 answer
  • The combustion method used to analyze for carbon and hydrogen can be adapted to give percentage N by collecting the nitrogen fro
    8·1 answer
  • . What percentage of the electricity in the United States is generated directly from solar energy?
    8·1 answer
  • Which type of fuel can only be used in certain geographic area? A. natural gas B. nuclear C. solar D. Biomass
    12·1 answer
  • for every 10 yards on a football field there I boldly marked line labeled with the amount of yards there are two parallel sideli
    7·1 answer
  • How is the AHfusion used to calculate the energy required to vaporize a
    12·1 answer
  • What is the molarity of a solution if 5 moles of solute are dissolved in 8 L of solvent.
    15·1 answer
  • β-Myrcene, a key intermediate in the production of several fragrances, is 7-methyl-3-methylene-1,6-octadiene.Draw the structure
    13·1 answer
  • What is the maximum amount of ammonia that can be produced when 0.35 mol Nz reacts with 0.90 mol Hz?
    7·1 answer
  • Elements found on the left side of the Periodic Table are known as
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!