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3 years ago

Calculate the ph of a solution whose(oh^-) is 4.583*10^-5 mole dm cube (pkw=14)

Chemistry

1 answer:

Sergeu [11.5K]3 years ago

8 0

pH of solution = 9.661

<h3>Further explanation </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.

pOH=-log[OH⁻]

$\tt pOH=-log[4.583\times 10^{-5}]\\\\pOH=5-log~4.583=4.339$

pH+pOH=pKw

$\tt pH=14-4.339\\\\pH=9.661$

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Calculate the ph of a solution whose(oh^-) is 4.583*10^-5 mole dm cube (pkw=14)​

Calculate the ph of a solution whose(oh^-) is 4.583*10^-5 mole dm cube (pkw=14)