The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.
<h3>How we calculate moles?</h3>
Moles of any substance will be calculated as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
2NI₃ → N₂ + 3I₂
Moles of 3.58g of NI₃ will be calculated as:
n = 3.58g / 394. 71 g/mol = 0.009 moles
From the stoichiometry of the solution, it is clear that:
2 moles of NI₃ = produce 3 moles of I₂
0.009 moles of NI₃ = produce 3/2×0.009=0.0136 moles of I₂
Hence, option (3) is correct i.e. 0.0136 moles.
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Answer:
9.63 L.
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
So the consumed amounts of hydrochloric acid and bromine are the same to the beginning based on:
In such a way, the yielded moles of hydrobromic acid and chlorine are:
Thus, the volume of the sample, after the reaction is the same as no change in the total moles is evidenced, that is 9.63L.
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Answer:
pH = 1.33
Explanation:
Because HCl is a strong acid, each mole of HCl will completely dissociate into H⁺ and Cl⁻ species.
Now we calculate the molar concentration (molarity) of H⁺:
- Molarity = moles / volume
(750 mL ⇒ 750 / 1000 = 0.750 L)
- Molarity = 0.035 moles / 0.750 L
Then we calculate the pH of the solution:
Because that solid is frozen liquid, so when it gets heated up, it will melt. Like Ice.
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