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Citrus2011 [14]
3 years ago
11

Consider g (x) = StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction Which statement correctly uses limits to de

termine the end behavior of g(x)? Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 Over 1 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 4. Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 4. Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0. Limit of StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction as x approaches plus-or-minus infinity = limit of StartFraction 4 x Over 1 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches infinity.
Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

To find the end behavior of a function, we find it's limits as x approaches infinity, getting the correct option as:

As x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0.

Function:

The function given is:

g(x) = \frac{4x+9}{x^6+1}

Limit as x goes to infinity:

To find the limit of a function as x goes to infinity, we consider the term with the highest exponent in the numerator and in the denominator. So

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{4x+9}{x^6+1} = \lim_{x \rightarrow \infty} \frac{4x}{x^6} = \lim_{x \rightarrow \infty} \frac{4}{x^5} = \frac{4}{\infty^5} = 0

The graphic of the function, given at the end of this answer, corroborates the answer.

Thus, the correct option is:

As x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0.

For more on limits as x approaches infinity, you can check brainly.com/question/12207599.

Lunna [17]3 years ago
5 0

Answer: C

Step-by-step explanation:

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Solve step by step solution then only i can do it plxx ​
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Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

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According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

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\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

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  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

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\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

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Answer:

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They both spoke for 7 minutes and therefore have the same amount of time left.

Algebraic expression:

Assuming the time Tom started with is denoted by x and the time he is left with is denoted by y.

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