The answer is 32. You have four trays each have 8 bars so multiply 8 and 4.
8*4=32
Answer:
A.Area of the base
Step-by-step explanation:
these is obtained by multiplying the length and width of the base to get the area of the base
Answer:
C
Step-by-step explanation:
You are choosing 3 from a total of 12. Order does not matter. So you are working with combinations. The answer symbolically is
12C3
12C3 = 12!/(9!3!)
12C3 = 12 * 11 * 10 * 9!/(9! 3!)
12C3 = 12 * 11 * 10/6
12C3 = 2 * 11 * 10
12C3 = 220
1. n^2 -8n +16 = 25
Subtract 25 from both sides
n^2 - 8n + 16 - 25 = 0
Simplify
n^2 - 8n - 9 =0
Factor
(n-9)(n+1) = 0
Solve for n
n-9 = 0, n = 9
n+1 = 0, n = -1
Solution: 9,-1
2. C = b^2/25
Multiply both sides by 25:
25c = b^2
Take square root of both sides
b = +/-√25c
Simplify:
b = 5√C, -5√C
3. d = 16t^2 +12t
subtract d from both side:
16t^2 + 12t -d =0
Use quadratic formula to solve:
t = (3 +/-√(9-4d))/8
4. 5w^2 +10w =40
Subtract 40 from both side:
5w^2 + 10w -40 = 0
Factor:
5(w-2)(w+4)=0
Divide both sides by 5:
(w-2)(w+4)=0
Solve for w:
w-2 = 0, w = 2
w+4=0, w = -4
Solution: 2,-4
Answer:
3 chocolate bars, and 2 graham crackers
Someone forgot the marshmallows...... :P
Step-by-step explanation:
Chocolate bars = 8 pack
Graham Crackers = 12pack
To have no crackers or chocolate left over, we need to find LCM
Factors of 8:
8, 16, 24, 32, 40, 48, 56, 72....
Factors of 12:
12, 24, 36, 48, 60, 72
The smallest LCM is 24
Chocolate bars:
24/8 = 3
Graham Crackers:
24/12 = 2
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-Chetan K
