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3 years ago

Describe and correct the error in finding the area of the triangle.

Mathematics

2 answers:

irina1246 [14]3 years ago

8 0

Answer:

Height, base(4,1) to A(4,3)

Step-by-step explanation:

The height that is shown is incorrect as it is showing the distance between A and B, which is not the height of the triangle, and simply a side. We need to find the altitude(height) which is a line perpendicular to the base. If we draw a line that is perpendicular to the base that intersects the highest point of the triangle, A, we get the point of intersection of that line and the base at (4,1)

adelina 88 [10]3 years ago

3 0

Answer: height; (4, 1) to (4, 3)

Step-by-step explanation:

Area of a triangle is (1/2) b × h where h is perpendicular to the base.

The base is correct - distance from (1, 1) to (4, 1).

The height is incorrect. It should be the distance from (4, 1) to (4, 3).

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Find the slope of the line on the graph. Write your answer as a fraction or a whole number, not mixed number or decimal.

Vesna [10]

Answer:

The slope is:

$m=-\frac{3}{2}$

Step-by-step explanation:

The slope m of a line is calculated using the following formula

$m=\frac{y_2-y_1}{x_2-x_1}$

Where the points $(x_1, y_1)$ and $(x_2, y_2)$ are two points belonging to the straight line

Notice in the graph that the line passes through the points

(0, 2) and (2, -1)

Then the slope is:

$m=\frac{-1-2}{2-0}$

$m=\frac{-3}{2}$

4 0

3 years ago

Anyone can help me solve this equation using cross multiplying

Natali5045456 [20]

9514 1404 393

Answer:

x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)$

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

$3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}$

_____

Comment on "cross multiply"

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes what the result looks like. It doesn't adequately describe how you get there. The one and only rule in solving Algebra problems is "whatever is done to one side of the equation must also be done to the other side of the equation." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "multiply by the product of the denominators and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}$

8 0

2 years ago

Its pretty easy if you are good at math! Please help!

aleksley [76]

Step-by-step explanation:

Explanation:

The trick is to know about the basic idea of sequences and series and also knowing how i cycles.

The powers of i will result in either: i, −1, −i, or 1.

We can regroup i+i2+i3+⋯+i258+i259 into these categories.

We know that i=i5=i9 and so on. The same goes for the other powers of i.

So:

i+i2+i3+⋯+i258+i259

=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)

We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.

=65(i)+65(i2)+65(i3)+64(i4)

From here on out, it's pretty simple. You just evaluate the expression:

=65(i)+65(−1)+65(−i)+64(1)

=65i−65−65i+64

=−65+64

=−1

So,

i+i2+i3+⋯+i258+i259=-1

8 0

3 years ago

Jethro wants a swimming pool in his backyard, so he digs a rectangular hole with dimensions 40 feet long, 20 feet wide, and 5 fe

Genrish500 [490]

4000 so the answer is C
Hope this helps

6 0

3 years ago

Write 492,053 in words form

umka21 [38]

Four Hundred Ninety two thousand Fifty Three.

6 0

3 years ago

Read 2 more answers

Describe and correct the error in finding the area of the triangle.​

Describe and correct the error in finding the area of the triangle.