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3 years ago

HELP PLSS QUICKLY!!!!

Mathematics

1 answer:

tigry1 [53]3 years ago

4 0

3 cans!!!

5x6= 30 (divided by 2= 15)
5x6=30 (divided by 2 = 15)
10x18= 180

180+30= 210

3 cans!!

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What is slope of the libe

Xelga [282]

The slope of a line usually determines id the line is negative or positive. For example, lines going uphill, or uphill slopes, are positive slopes. The slope will be a positive number such as, yet not limited to, 5, 10, or 57. Or you can also take their counter parts for example, downhill slopes would be considered negative slopes, meaning they go below zero, instead of above, like positive slopes. Hope this helps. :D

7 0

3 years ago

Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement.

Mrrafil [7]

Answer:

$E(X_n)=\frac{2(n-1)}{27}$

$E(y)=\frac{14}{9}$

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green $g=4$

Number of yellow $y=4$

Number of white $w=4$

Probability of Green Followed by yellow P(GY) ball

$P(GY)=\frac{4}{9}*\frac{3}{9}$

$P(GY)=\frac{4}{27}$

Generally the equations for when n is even is mathematically given by

$Probability of success P(S)=\frac{4}{27}$

$Probability of Failure P(F)=\frac{27-4}{27}$

$Probability of Failure P(F)=\frac{23}{27}$

Therefore

$E(X_n)=\frac{n}{2}*P$

$E(X_n)=\frac{n}{2}*\frac{4}{27}$

$E(X_n)=\frac{2n}{27}$

Generally the equations for when n is odd is mathematically given by

$\frac{n-1}{2}$

$E(X_n)=\frac{n-1}{2}*\frac{4}{27}$

$E(X_n)=\frac{2(n-1)}{27}$

Probability of drawing white ball

$P(w)=\frac{2}{9}$

Therefore

$E(w)=\frac{1}{p}$

$E(w)=\frac{1}{\frac{2}{9}}$

$E(w)=\frac{9}{2}$

Therefore

$E(y)=[E(w)-1]\frac{4}{9}$

$E(y)=[\frac{9}{2}-1]\frac{4}{9}$

$E(y)=\frac{14}{9}$

5 0

3 years ago

If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle

melamori03 [73]

Let's assume they meant C=40 degrees. With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

$AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C$

$AB^2 = AC^2 + BC^2 - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ$

$AB = \sqrt{ 169 - 120 \cos 40 ^\circ} \approx 8.77921789$

The area is $\frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628$

The circumradius is $r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) } = 6.829019329$

5 0

3 years ago

On the unit circle, which of the following angles has the terminal point coordinates (√2/2,-√2/2)

aleksandr82 [10.1K]

Answer:

Option B

Step-by-step explanation:

A unit circle means radius of the circle = 1 unit

Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.

Center of the circle is origin (0, 0).

Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = $(\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})$