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3 years ago

13

Mr Abraham is able to divide the learners in his mathematics class into equal groups of 2, 5 or 6 without leaving any learners o

ut. What is the smallest possible number of learners in the class

1 answer:

IRISSAK [1]3 years ago

3 0

Answer:

30

Step-by-step explanation:

Find the lowest number divisible by both 6, 5, and 2.

To start, let's list off the numbers divisible by six, and see if we can check any of them off for 5. Since both 2 and 6 are even numbers, we know that if a number is divisible by 6, it's divisible by 2.

6 12 18 24 30 36 42 48 54 60

All of these numbers are divisible by two. Let's find the lowest one that is divisible by 5. We know this by either the umber ending in 5 or 0.

30 is the lowest number that is divisible by 2, 5, or 6.

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Which expressions are quadratic expressions? Check all that apply.

tensa zangetsu [6.8K]

Answer:

2x + 7x – 10

2x2 + 9x – 7

Step-by-step explanation:

5 0

3 years ago

A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

4 0

4 years ago

4 thousands 7 hundreds =47

aliya0001 [1]

It is 4,700 for the answer

5 0

3 years ago

!!!!I'LL MARK YOU BRAINLIEST!!!! PLZ ANSWER CORRECTLY!!<br> HOW MANY OUNCES ARE IN LITERS

kondor19780726 [428]

Answer: 1 ounce = 0.0295735 liters rounded it is 0.03 liters

Formula: Divide the volume value by 33.814

1÷33.814 =0.0295735

0.02957354941 rounded to the nearest hundredths is 0.03

3 0

3 years ago

Read 2 more answers

Please answer I need step by step explanation

olya-2409 [2.1K]

Answer:

10 cm

Simplified explanation/tl;dr: the small triangle is two thirds the size of the big triangle, so the missing side on the small triangle is two thirds the size of the same side on the big triangle

Long explanation/step by step:

It looks scary, but don't worry; for questions like this just find the ratio then multiply it by the similar side to find the missing side.

This is what I mean: 8/12 simplified is 2/3 (4 is the common factor and 8/4 = 2 and 12/4 = 3). That's your fraction to multiply by.

I chose 8 and 12 because look how the triangles are the same shape just different sizes, that means they're similar. the similar sides are just the same side on both triangles. (for this one, BC and GH are similar). to find how much smaller it is in fraction form, you just take two of the same sides and divide the small one by the big one. (big number becomes top, small becomes bottom)

now just multiply 15 by 2/3 by using fraction multiplication. 15/1 x 2/3 = 30/3. Simplify that to 10/1 (3 is the common factor and 30/3 = 10 and 3/3 = 1). 10/1 = 10.

7 0

3 years ago