<em><u>The cost of production equation is:</u></em>
C = 10n + 20000
<em><u>Solution:</u></em>
<em><u>The equation representing the cost, C, of producing n tires at Royal Tires Co. can be written as:</u></em>
C = mn + f
Where,
C = cost
n = number of tires
f = company's fixed cost
<em><u>It costs $30,000 to produce 1,000 tires while it costs $50,000 to produce 3,000 tires</u></em>
Therefore,
30, 000 = m(1000) + f
50, 000 = m(3000) + f
Which is,
1000m + f = 30000 ------- eqn 1
3000m + f = 50000 ------- eqn 2
Subtract eqn 1 from eqn 2
3000m + f = 50000
1000m + f = 30000
( - ) -------------------
2000m = 20,000
m = 10
Substitute m = 10 in eqn 1
1000(10) + f = 30000
f = 30000 - 10000
f = 20,000
Thus the equation is:
C = 10n + 20000
40% = 40/100 = 0.40
Find 40% of 20
20 * 0.40 = 8
Solution: 8 students traveled
Answer:
x + 2.6 = 10.4
x = 7.8
Step-by-step explanation:
If 2.6 liters are added to x liters with the result that 10.4 liters then exist, the model is ...
2.6 +x = 10.4 . . . . . . . 2.6 added to x gives 10.4
The commutative property of addition lets you rewrite this to ...
x +2.6 = 10.4
__
Subtracting 2.6 from both sides of the equation gives its solution:
x +2.6 -2.6 = 10.4 -2.6
x = 7.8
Answer:
1.Three and Nine Hundredths 2. 3 9/100 3. 390%
Step-by-step explanation:
