Well, it was good that you did subtract A from B to get
0=x^2-152x
then factor out the x (what do you mean it cannot be factored?)
0=x(x-152)
x=0 or 0=x-152 so x=152
so on day 0 and day 152
In a box and whisker plot, the Median is represented by the line at the center of the box.
So, from the above figures we can see that the Median for the Class Data is around 82 and the median for the Exam Data is around 87. It is clear that the Median of Exam data is higher than the Median of Class Data.
So, the best statement to describe the medians will be the option C. The class median is lower than the exam median. The option A and B are not correct. The outlier does have not have much of a large impact on the median of the data and neither the spread of the data primarily determines its median. Median only depends on the number of values in the data set.
Therefore, the correct answer is option C
To find out how much you need when you need a fraction of a number like 1/3 of 9, you can multiply the whole number by the fraction in most cases.
In some cases however, you can convert the whole number into a fraction and then divide it to get the amount in fractional units that you require.
For example:
1/3 of 9
Convert 9 to a fraction.
1/3 / 9/1
1/3 x 9/1 = 3/9
Therefore you would need 3 of 9 for 1/3.
Answer:
B) 24/35
Step-by-step explanation:
Cos(X)= Adjacent/Hypotenuse
Cos(X) = 24/25
Therefore, option B is your answer.
Hope this answers your question!!
