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3 years ago

HELP ME ASAP PLEASE!! IM GIVING EXTRA POINTS AND BRAINLIEST!!

Mathematics

1 answer:

Masja [62]3 years ago

3 0

Answer:

the second one listed would be the answer you're looking for hon.

Step-by-step explanation:

Don't stay up too late, it is getting late. make sure you ace whatever you are doing and get good rest too.

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5(3) + 2
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Your answer is 17

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3 years ago

Skills Practice: convert the following fractions into decimals. You must show your

Lina20 [59]

ANSWER:
0.25

i attached my work, hope this helps

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3 years ago

Write and solve a real-world problem that represents the following one-variable inequality.

serg [7]

Hello there! An example problem for this could be:
Emile is looking for a cell-phone plan. His two options are one that costs $40 up front, and costs $0.01 per text, represented by x. The second one is 15 dollars up front and costs $0.06 for each text message. Emile figures that for the first package he has to send 500 texts or more to make it less than the second one.

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3 years ago

Which ordered pair is a solution of the equation -x-4y=-10

Ilia_Sergeevich [38]

Answer:

There are many possible solutions. Here are some:

(-2,12) (2,2) (6,1) (10,0) (-6,4)

Step-by-step explanation:

hope it helps

3 0

3 years ago

Read 2 more answers

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago