Answer:
7) 10^(3/2)
8) 2^(1/6)
9) 2^(5/4)
10) 5^(5/4)
Step-by-step explanation:
7) (√10)^3 = 10^(3/2)
8) 6 root 2 = 2^(1/6)
9) (4 root 2)^5 = 2^(5/4)
10) (4 root 5)^5 = 5^(5/4)
Answer:
down ⬇⬇⬇
Step-by-step explanation:
5. its all of them so just write A, B, C, D, E, F, G
6. (equilateral) triangle, right triangle, diamond (?), parallelogram
7. C and E; A and B
8. not so sure about this one but i think its regular
9. its not a polygon because polygons have straight sides, and this figure does not.
10. the only polygon is C
pay attention in school, it'll help in the long run. even if it sounds boring, it will come in handy one day!!
hope this helped <33333
We're told that
where the last fact is due to the law of total probability:
so that 
and 
are complementary.
By definition of conditional probability, we have
We make use of the addition rule and complementary probabilities to rewrite this as
![\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)](https://tex.z-dn.net/?f=%5Cimplies%20P%28B%29-%5B1-P%28A%5Ccup%20B%29%5EC%5D%3D%5B1-P%28B%29%5D-P%28A%5Ccup%20B%5EC%29)
![\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]](https://tex.z-dn.net/?f=%5Cimplies2P%28B%29%3D2-%5BP%28A%5Ccup%20B%29%5EC%2BP%28A%5Ccup%20B%5EC%29%5D)
![\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]](https://tex.z-dn.net/?f=%5Cimplies2P%28B%29%3D%5B1-P%28A%5Ccup%20B%29%5EC%5D%2B%5B1-P%28A%5Ccup%20B%5EC%29%5D)
By the law of total probability,
and substituting this into 
gives
![2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]](https://tex.z-dn.net/?f=2P%28B%29%3DP%28A%5Ccup%20B%29%2B%5BP%28B%29-P%28A%5Ccap%20B%29%5D)
