It is already given in the question that that freezing temperature of water is 0 degree Celsius. The freezing temperature of water in degree Fahrenheit is required to be found.
We know the relation between degree centigrade and degree Fahrenheit is"
Degree Fahrenheit = C(9/5) + 32
Here in the above equation "C" represents degree centigrade.
From the question we already know the freezing temperature of water as 0 degree Centigrade. Now we have to replace the value of Centigrade in the equation
Degree Fahrenheit = C(9/5) + 32
= 0(9/5) + 32
= 0 + 32
= 32 degrees
So water freezes at 32 degrees Fahrenheit.
Solve for K by simplifying both sides of the function, then isolating the variable.
k = -f (x) + gx
Answer:
(7.13 × 10^-3) x 40 = 285.2 x 10^-3 = 2.9 x 10^-1
Step-by-step explanation:
I think this is the answer i hope if it right or not but aleast I try on it .
Answer:
22 miles per hour
Step-by-step explanation:
Against the current, the boat's rate of travel is ...
(120 mi)/(6 h) = 20 mi/h
With the current, the boat's rate of travel is ...
(120 mi)/(5 h) = 24 mi/h
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The sum of boat speed (b) and current speed (c) is 24 mph. The difference is 20 mph. This lets us write the equations ...
b + c = 24
b - c = 20
Adding these two equations together, we get ...
2b + 0c = 44
b = 22 . . . . . . . . divide by 2
The rate of the boat in still water is 22 miles per hour.
Answer:
the answer is -117/424, hope this helps :)
