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SashulF [63]
3 years ago
6

Please hurry...

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer:

Which formula can be used to find the surface area of the hemisphere? ... Recall that the formula for the volume for a sphere is v=4/3πr^3 and the ... Type A is a spherical ball with a radius of 12 inches. ... r=6cm. SA=1/2(4πr^2)+πr^2. SA=2π(6)^2+π(6)^2. SA=72(3.14)+36(3.14) ... The diameter of the hemisphere is 48 feet.

Step-by-step explanation:

DochEvi [55]3 years ago
5 0

Answer:

Which formula can be used to find the surface area of the hemisphere? ... Recall that the formula for the volume for a sphere is v=4/3πr^3 and the ... Type A is a spherical ball with a radius of 12 inches. ... r=6cm. SA=1/2(4πr^2)+πr^2. SA=2π(6)^2+π(6)^2. SA=72(3.14)+36(3.14) ... The diameter of the hemisphere is 48 feet.

Step-by-step explanation:

You might be interested in
Gizmo is investing in TikTok stock. He plans on adding an additional $250 at the end of every year and the expected monthly rate
Nikitich [7]

Answer:

y=425*250^1.083

Step-by-step explanation:

It wants to write an equation of that models the amount of money in the account each month for the first year.

We need the Exponential Equation Formula: y=a*bx

Y is the amount of money in the account.

a is the initial amount he starts with

b is the amount being added each month

x is the rate of return

So, y=425*2501.083

8 0
3 years ago
Read 2 more answers
Please, I need help in this ??
nignag [31]

Answer:

\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c

Step-by-step explanation:

\int\frac{x^{4}}{x^{4} -1}dx

Adding and Subtracting 1 to the Numerator

\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx

Dividing Numerator seperately by x^{4} - 1

\int 1 + \frac{1}{x^{4}-1 }\, dx

Here integral of 1 is x +c1 (where c1 is constant of integration

x + c1 + \int\frac{1}{(x-1)(x+1)(x^{2}+1)}\, dx----------------------------------(1)

We apply method of partial fractions to perform the integral

\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}------------------------------------------(2)

\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}

1 = A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)-------------------------(3)

Substitute x= 1 , -1 , i in equation (3)

1 = A(1+1)(1+1)

A = \frac{1}{4}

1 = B(-1-1)(1+1)

B = -\frac{1}{4}

1 = C(i-1)(i+1)

C = -\frac{1}{2}

Substituting A, B, C in equation (2)

\int\frac{x^{4}}{x^{4} -1}dx = \int\frac{1}{4(x-1)} - \frac{1}{4(x+1)} -\frac{1}{2(x^{2}+1) }

On integration

Here \int \frac{1}{x}dx = lnx and \int\frac{1}{x^{2}+1 } dx = arctanx

\int\frac{x^{4}}{x^{4} -1}dx = \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2---------------------------------------(4)

Substitute equation (4) back in equation (1) we get

x + c1 + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2

Here c1 + c2 can be added to another and written as c

Therefore,

\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c

4 0
4 years ago
Carl plans to invest $500 at 8.25% interest, compounded continuously. How long will it take the money to triple?
gogolik [260]
Use exponential growth equation.
8 0
3 years ago
Please answer please
Murrr4er [49]

<BAC = <DEC = 30°

<BCA = <DCE = 70°

<CDE (or m<D) = 180° - <DEC - <DCE

<CDE = 180° - 30° - 70°

<CDE = 80°

The number that belongs in the green box is 80

3 0
4 years ago
Examine the following table. Determine whether the rate of change is constant or variable. If it is constant, state the rate of
xenn [34]

Answer:

Variable rate of change.

Step-by-step explanation:

Plot the points and you'll see that the graph is not a straight line, therefore the rate of change is variable.

5 0
3 years ago
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