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levacccp [35]
3 years ago
15

11. To make sure that your guests don't get food poisoning at Thanksgiving dinner, you decide to use a pop-up

Chemistry
1 answer:
ohaa [14]3 years ago
3 0

Answer:

Do not use this exact photo please!

Explanation:

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The answer is B. It will grow towards the hole in the box because the plant will try and get as close to the sunlight as possible which is called phototropism.
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If atoms really conformed to the plum pudding model of the atom, what would the results of rutherford’s experiment have been?
Hitman42 [59]
Rutherford's experiment was done to prove Thompson's Plum Pudding Model. In this model, the protons and electrons are both inside the nucleus. The atoms is neutral because the charges cancel out. Rutherford's hypothesis was that, when a beam of cathode rays hits the gold foil, all the light should pass through. If the Plum Pudding model was correct, that would have been the result. However, it wasn't. 
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3 years ago
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There are 12 inches (in). in 1 foot (ft). which expression can be used to find the number of inches in 2.5 feet?
Nady [450]
Given:
12 inches in 1 foot
number of inches in 2.5 feet

2.5 feet * 12 inches/1foot = 2.5 * 12 inches = 30 inches

1 foot + 1 foot + 0.5 foot = 2.5 feet
12 inches + 12 inches + 6 inches = 30 inches

12 inches : 1 foot = x : 2.5 feet
12 inches * 2.5 feet = x*1foot
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4 0
3 years ago
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How many grams of H2O will be formed when 32.0 g H2 is mixed with 84.0 g of O2 and allowed to react to form water
Zarrin [17]

Answer:

94.58 g of H_2O

Explanation:

For this question we have to start with the reaction:

H_2~+~O_2~->~H_2O

Now, we can balance the reaction:

2H_2~+~O_2~->~2H_2O

We have the amount of H_2  and the amount of O_2 . Therefore we have to find the limiting reactive, for this, we have to follow a few steps.

1) Find the moles of each reactive, using the molar mass of each compound (H_2~=~2~g/mol~~O_2=~32~g/mol ).

2) Divide by the coefficient of each compound in the balanced reaction ("2" for H_2 and "1" for O_2).

<u>Find the moles of each reactive</u>

32.0~g~H_2\frac{1~mol~H_2}{2~g~of~H_2}=15.87~mol~H_2

84.0~g~of~O_2\frac{1~mol~of~O_2}{32~g~of~O_2}=2.62~mol~of~O_2

<u>Divide by the coefficient</u>

<u />

\frac{15.87~mol~H_2}{2}=7.94

\frac{2.62~mol~of~O_2}{1}=2.62

The smallest values are for H_2, so hydrogen is the limiting reagent. Now, we can do the calculation for the amount of water:

32.0~g~H_2\frac{1~mol~H_2}{2~g~of~H_2}\frac{2~mol~H_2O}{2~mol~H_2}\frac{18~g~H_2O}{1~mol~H_2O}=94.58~g~H_2O

We have to remember that the molar ratio between H_2O and H_2 is 2:2 and the molar mass of H_2O is 18 g/mol.

6 0
3 years ago
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