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2 years ago

How many grams of Cl2 are in 0.345L at STP?

Chemistry

1 answer:

blsea [12.9K]2 years ago

3 0

Answer: 1.09 g

Explanation:

If we use the approximation that 1 mole is 22.4 L, then setting up a proportion,

1/22.4 = x/0.345 (x is the number of moles in the sample)
x = 0.0154 mol

Since the mass of a mole of chlroine is about 70.9 g/mol, (0.0154)(70.9) = 1.09 g (to 3 s.f.)

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Which of these statements is not true about chemical reaction rates

grin007 [14]

Answer: The statement (B) is not true about chemical reactions.

Explanation:

A chemical reaction rate is affected by the several factors few of which are temperature, concentration of reactants, surface area etc.

In a chemical reaction, if temperature is increased then the rate of reaction will increase because it will increase the average kinetic energy of the reactant molecules. Thus, large number of molecules will have minimum energy required for an effective collision.

It is known that increasing the amount of reactants will increase the rate of reaction.

Therefore, rate of reaction will change if concentration or temperature is changed.

Hence, the statement (B) is not true about chemical reactions.

6 0

3 years ago

Read 2 more answers

Choose all the answers that apply.

zmey [24]

Calcium is a non metal

5 0

3 years ago

Read 2 more answers

If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce

Natali5045456 [20]

2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over

5 0

3 years ago

The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of

denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

$Kb=\frac{[IBH^+][OH^-]}{[IB]}$

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

$pOH=14-8.20=5.80$

$[OH^-]=10^{-5.8}=1.585x10^{-6}M$

$Kb=10^{-5.20}=6.31x10^{-6}$

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

$6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}$

Finally, we solve for the equilibrium concentration of ibuprofen:

$[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}$

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

4 0

2 years ago

I need help with Chemistry: Mole Conversion<br> It must be answered in complete detail

Anni [7]

Answer:

As Per Given Information

Number of moles SO₂ ( Sulphur dioxide ) is 0.30

We 've been asked to find the number of atoms in given moles of Sulphur dioxide .

Value of Avogadro Number is 6.022 × 10²³ mol⁻¹

For finding the number of atoms we will use formale

$\underline{\boxed{\textbf{\textsf{ Number \: of \: atoms \: = Given \: moles \: . Avogadro \: number}}}}$

Putting the given value we obtain

$\sf \twoheadrightarrow \: Number \: of \: atoms \: = 0.30 \times 6.022 \times {10}^{ 23} \\ \\ \sf \twoheadrightarrow \: Number \: of \: atoms \: = \: 1.8066 \times {10}^{ 23} atoms$

So, the number of atoms in sulphur dioxide is 1.8066 × 10²³

8 0

1 year ago