Answer:
0.9 L.
Explanation:
The following data were obtained from the question:
Molarity of stock solution (M1) = 10 M
Molarity of diluted solution (M2) = 1 M
Volume of stock solution (V1) = 100 mL
Volume of water needed =.?
Next, we shall determine the volume of the diluted solution. This can be obtained as follow:
Molarity of stock solution (M1) = 10 M
Molarity of diluted solution (M2) = 1 M
Volume of stock solution (V1) = 100 mL
Volume of diluted solution (V2) =.?
M1V1 = M2V2
10 × 100 = 1 × V2
1000 = V2
V2 = 1000 mL
Next, we shall determine the volume of water needed. This can be obtained as follow:
Volume of stock solution (V1) = 100 mL
Volume of diluted solution (V2) = 1000 mL
Volume of water needed =?
Volume of water needed = (Volume of diluted solution) – (Volume of stock solution)
Volume of water needed = V2 – V1
Volume of water needed = 1000 – 100
Volume of water needed = 900 mL
Finally, we shall convert 900 mL to litre (L). This can be obtained as follow:
1000 mL = 1 L
Therefore,
900 mL = 900 mL × 1 L / 1000 mL
900 mL = 0.9 L
Therefore, the volume of water needed to dilute the solution is 0.9 L.
