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2 years ago

I’m just trynna get to 90% on this test before sunrise

Mathematics

1 answer:

Ipatiy [6.2K]2 years ago

8 0

Answer:

they are congruent

Step-by-step explanation:

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Simplify:

wlad13 [49]

Answer:

39/25

Step-by-step explanation:

i use a very good app to find the answer

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3 years ago

What is the conjugate of -2 + 8i

topjm [15]

Answer:

-2 - 8i

Step-by-step explanation:

To find the conjugate of a complex number, change the sign of the imaginary part.

The conjugate of -2 + 8i is -2 - 8i.

3 0

3 years ago

Find the slope and the y-intercept of the graph of the linear equation. y = 6x

Snowcat [4.5K]

Y-intercept=0
slope=6/1

hope this helps

4 0

4 years ago

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: Confidence Interval is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

3 years ago

Find the area of each sector. Omg please help due in 5 min!!

mr Goodwill [35]

The answer is C (289pi/6 mi2)

5 0

3 years ago