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2 years ago

6

Will had 64 baseball cards in his collection. He then got 8 more cards. He keeps the cards in a binder. Each page in the binder

can hold 9 cards. Complete and solve the equations below to find how many pages of baseball cards Will has.

1 answer:

WITCHER [35]2 years ago

6 0

Answer: 64+8=72...72/9=8

Step-by-step explanation:

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What is the area of this figure?

sergiy2304 [10]

$1.5 \times 3 = 4.5 \: {(km)}^{2}$

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2 years ago

What is 35% of 76.6?

aleksandrvk [35]

Answer:

26.6

Step-by-step explanation:

Solution for What is 35 percent of 76:

35 percent *76 =

( 35:100)*76 =

( 35*76):100 =

2660:100 = 26.6

Now we have: 35 percent of 76.6 = 26.6

Therefore, 35% of 76.6 is 26.6

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2 years ago

Latoya's annual salary is $26,000. A total of $7352.24 will be deducted for taxes and health insurance. She will receive her pay

Anna71 [15]

Step-by-step explanation:

Lets translate this word problem into math.

"Latoya's annual salary is $26,000" = We start with the number 26,000

"A total of $7352.24 will be deducted for taxes and health insurance" = It's the number we started with "deducted" (minus) 7352.24

"She will receive her paycheck monthly in 12 equal installments" = Our number will be divided by 12

"How much will she get paid with each paycheck?" = "Find answer pls thx"

To put it all together...

$\frac{26,000-7,352.24}{12}$

Now all we have to do is solve!

$\frac{26,000-7,352.24}{12}$

Subtract.

$\frac{18,647.76}{12}$

Divide.

$1,553.98$

Answer:

Latoya will get paid $1,553.98 with each paycheck.

7 0

2 years ago

Please Help! Easy!

irinina [24]

Answer:

The answer is B.

4 0

3 years ago

Read 2 more answers

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

2 years ago