All categories

3 years ago

Identify the range of the function shown in the graph.

Mathematics

1 answer:

lys-0071 [83]3 years ago

7 0

Answer:

C. 0 ≤ y ≤ 8

Step-by-step explanation:

In any graph, the range represents the 'y' values covered by the graph. The 'y' axis is the vertical (up and down) line on the graph. Given the graph, it stops at the point (0, 8) on the top and at (-6,0) and (6,0) on the bottom. This would be an overall range of 0 ≤ y ≤ 8.

You might be interested in

Which decimal is equivalent to 26/9

grandymaker [24]

Answer:

The decimal 2.8 is equivalent to 26/9

Hope this helps

3 0

2 years ago

How much is 74 divided by 4

exis [7]

Answer:

18.5

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The height, h, in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t 2 + 64t,

coldgirl [10]

Answer:

4 seconds

Step-by-step explanation:

When the ball is on the ground h = 0, hence

- 16t² + 64t = 0 ( solve for t )

factor out - 16t

- 16t(t - 4) = 0

equate each factor to zero and solve for t

- 16t = 0 ⇒ t = 0

t - 4 = 0 ⇒ t = 4

the 0 solution is the height of the ball before being hit and

the time the ball takes to hit the ground is 4 seconds

6 0

3 years ago

1.13 Thank you! (Sorry it’s so blurry)

VikaD [51]

$\sqrt[8]{48^4}$ can be rewritten as $48^4$ to the $\frac{1}{8}$ power:

$(48^4)^ \frac{1}{8}$

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

$(48^ \frac{1}{2})$

This is equivalent to $\sqrt{48}$ , so now, we just simplify:

$\sqrt{48}= \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}$

So:

$\sqrt[8]{48^4} =4 \sqrt{3}$

4 0

3 years ago

If M is the midpoint of PQ and X is the midpoint of PM then PX = a PQ Which statement is True? a is equal to 1 a is equal to 1/2

garik1379 [7]

Answer:

D. a is equal to $\frac{1}{4}$

Step-by-step explanation:

Let us assume that segment PQ is 8 units, so that its midpoint M is at 4 units to both P and Q.

Given that X is the midpoint of PM, this implies that X is at 2 units to both P and M.

Then;

PX = aPQ

⇒ = a x 8

= 8a

Therefore, a must be equal to $\frac{1}{4}$ , so that;

PX = 8a

= 8 x $\frac{1}{4}$

= 2 units

Thus, a is equal to $\frac{1}{4}$ is the correct option.

6 0

3 years ago

Identify the range of the function shown in the graph.​

Identify the range of the function shown in the graph.