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3 years ago

Read the excerpt from act 1 of The Monsters Are Due on Maple Street.

Mathematics

2 answers:

Vika [28.1K]3 years ago

5 0

Answer:

it is D. the murmurs of a group

Step-by-step explanation:

Alisiya [41]3 years ago

4 0

Answer:

Step-by-step explanation:

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I need help ASAP <br>If ANYONE gets it right will be given <br>BRAINLIEST!!!

kifflom [539]

Last one 9 46/180

It's actually pretty basic

4 0

2 years ago

Read 2 more answers

3/5 x 1/5+1/5 x 73/3

insens350 [35]

So,

3/5 x 1/5 = 3/25

3/25 + 1/5 = 8/25

8/25 x 73/3 = 7 59/75

I hope this helps

5 0

3 years ago

A value meal package at Ron's Subs consists of a drink, a sandwich, and a bag of chips. There are 5 types of drinks to choose fr

Lynna [10]

Answer: 90 different meal packages.

Step-by-step explanation:

Given data:

Types of drinks available = 5

Types of sandwiches available = 6

Types of chips available = 3.

Solution:

No of meal packages possible for this combination

= 6*5*3

= 90

A total of 90 different meal packages would be gotten:

8 0

2 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.