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yaroslaw [1]
2 years ago
11

Find the original price

Mathematics
2 answers:
Alex73 [517]2 years ago
7 0
X is the original price

x -0.25x = 40
0.75x = 40, divide both sides by 0.75
x = 53.34
schepotkina [342]2 years ago
3 0

Answer: $50

Step-by-step explanation:

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ALGEBRA<br> EQUATION<br> PLEASE HELP ASAP<br><br> -3=12y-5(2y-7)
Dovator [93]

Simplify:

−3=12y−5(2y−7)

−3=12y+(−5)(2y)+(−5)(−7)(Distribute)

−3=12y+−10y+35

−3=(12y+−10y)+(35)(Combine Like Terms)

−3=2y+35

Flip the equation.

2y+35=−3

Subtract 35 from both sides.

2y+35−35=−3−35

2y=−38

Divide both sides by 2.

2y/2=−38/2

y=−19


3 0
3 years ago
Read 2 more answers
LCM of x&lt;sup&gt;2&lt;/sup&gt;+5x+6 and x&lt;sup&gt;2&lt;/sup&gt;-x-6 is ………………………
sergejj [24]

Answer:

(x^2 - 9)(x + 2)

Step-by-step explanation:

Given:

x^2 + 5x + 6

x^2 - x - 6

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

x^2 + 5x + 6

x^2 + 3x + 2x + 6

(x^2 + 3x) + (2x + 6)

x(x + 3) + 2(x + 3)

(x + 2)(x + 3)

x^2 - x - 6

x^2 - 3x +2x - 6

x(x - 3) + 2(x - 3)

(x + 2)(x - 3)

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

x^2 + 5x + 6 = (x + 2)(x + 3)

x^2 - x - 6 = (x + 2)(x - 3)

The common factors would be: =>

(x + 2) (this is common in both polynomials, so we would take just one of them as a factor.

(x + 3) and,

(x - 3)

Their product = (x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)

4 0
3 years ago
How can 4.17 be written as a whole number with a fraction?
solmaris [256]
It can be written as 4 17/100
3 0
3 years ago
The product of a number and 3 is 87 what is the number
IrinaK [193]
The awnser would be 29
8 0
2 years ago
Read 2 more answers
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
Read 2 more answers
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