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2 years ago

9

Se tiene en una caja 6 bolas blancas y 5 bolas negras. ¿Cuántas bolas se debe extraer como mínimo para tener la certeza de haber

extraido dos del mismo color?

1 answer:

vodomira [7]2 years ago

3 0

Answer:

7 bolas

Step-by-step explanation:

Aquí, queremos saber el número de bolas que se deben sacar para estar seguros de haber extraído al menos dos bolas del mismo color.

De la pregunta, hay 6 tipos y 5 tipos de bolas diferentes. Así que en caso de que saquemos 6 veces y tuviéramos las mismas bolas, estaríamos seguros de que en el séptimo sorteo estaremos cogiendo una bola de otro color ya que hemos agotado el número de bolas del primer tipo y nos queda solo con las bolas del segundo tipo.

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Find the value of a.<br> A. 58<br> B. 130<br> C. 86<br> D. 65

tatiyna

Answer:

$C. \ \ \ 86$ °

Step-by-step explanation:

1. Approach

In order to solve this problem, one must first find a relationship between arc (a) and arc (c). This can be done using the congruent arcs cut congruent segments theorem. After doing so, one can then use the secants interior angle to find the precise measurement of arc (a).

2. Arc (a) and arc (c)

A secant is a line or line segment that intersects a circle in two places. The congruent segments cut congruent arcs theorem states that when two secants are congruent, meaning the part of the secant that is within the circle is congruent to another part of a secant that is within that same circle, the arcs surrounding the congruent secants are congruent. Applying this theorem to the given situation, one can state the following:

$a = c$

3. Finding the degree measure of arc (a),

The secants interior angle theorem states that when two secants intersect inside of a circle, the measure of any of the angles formed is equal to half of the sum of the arcs surrounding the angles. One can apply this here by stating the following:

$86=\frac{a+c}{2}$

Substitute,

$86=\frac{a+c}{2}$

$86=\frac{a+a}{2}$

Simplify,

$86=\frac{a+a}{2}$

$86=\frac{2a}{2}$

$86=a$

5 0

3 years ago

Consider the following game, played with three standard six-sided dice. If the player ends with all three dice showing the same

ddd [48]

Answer:

a

$P(A) = \frac{1}{36}$

b

$P(B) = \frac{15}{36}$

c

$P(U) = \frac{11}{36}$

Step-by-step explanation:

From the question we are told that

The number of dice is $n = 3$

Generally for all three dice to show the same number the second and the third dice must have the same outcome as the outcome of the first dice.

This means that the number of outcome the first die can have is 6 (6 sides), the number of outcome which the second and the third dice can have is 1 (they must match the first )

So the probability that all three dice show the same number on the first roll is mathematically represented as

$P(A) = \frac{6}{6} * \frac{1}{6} * \frac{1}{6}$

=> $P(A) = \frac{1}{36}$

Generally for two of the three dice show the same number after the first roll then the number of outcome for one of the dice would be is 6 , the number of outcome for another one must be 1(i.e it must match the first ) , the number of outcome for the remaining one must be 5 (i.e it can show any of the remaining 5 sides which the first and second dice are not showing )

Now the number of ways of selecting this 2 dice that show the same number from the 3 dice is mathematically represented as

$N = ^3C_2$

Here C stands for combination

So

$N = ^3C_2 = 6$

So the probability that exactly two of the three dice show the same number after the first roll is mathematically represented as

$P(B) = N \frac{1}{6} * \frac{5}{6}$

=> $P(B) = \frac{15}{36}$

Generally from the question we are told that if two dice match, the player re-rolls the die that does not match.

Now the probability that the die that did not match the first time will match the second time is

$P(E ) = \frac{1}{6}$

Generally if that one die does not show the same number in the second round , the probability that it will match in the third round is

$P(R) = \frac{5}{6} * \frac{1}{6}$

Generally the probability that he wins (i.e when all three are showing the same number ) and exactly two is showing the same number is mathematically represented as

$P(K) = P(E)* P(B) + P(R)* P(B)$

=> $P(K) = \frac{1}{6} * \frac{15}{36} + \frac{5}{6} * \frac{1}{6} * \frac{15}{36}$

=> $P(K)= \frac{165}{1296}$

So the probability that the player wins, conditioned on exactly two of the three dice showing the same number after the first roll is mathematically represented as

$P(U) = \frac{\frac{165}{1296}}{\frac{15}{36} }$

=> $P(U) = \frac{11}{36}$

6 0

3 years ago

PLS HELP, I’m soo confused!!! ANY HELP WILL BE APPRECIATED

Ilia_Sergeevich [38]

Answer:

e

Step-by-step explanation:

e

6 0

2 years ago

If a cylender has a volume of 340ft and a radius of three ft what is the height

rewona [7]

Answer:

h = 12.03

Substitute 22÷7 for pi.

h = V ÷ πr²

h = 340 ÷ (22÷7) × 3²

≈ 12.03

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2 years ago

Please help with this work I can't seem to find the answers to any of them, THANK YOU!

Brilliant_brown [7]

Answer:

Dude, that was not nice he just wants to know!

Step-by-step explanation:

6 0

3 years ago