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juin [17]
3 years ago
15

Determine the Slope for the following ordered pairs: (3,9) (3,21) (5,13) (3,13)

Mathematics
1 answer:
Mumz [18]3 years ago
8 0

Answer:

-4

Step-by-step explanation:

All you have to do is find the change of y over the change of x.

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6. they were 300 people at a football match and 35% were adults, the rest were children a. what percentage were children​
ioda

Answer: 65%, 195 children

Step-by-step explanation: To get this, we just do 100-35 to get 65 percent. We can calculate this further, and do 300*0.65, and we get 195. Thus, there were 195 children.

4 0
2 years ago
Read 2 more answers
Find the area of the regular polygon. Round to the nearest tenth.
JulsSmile [24]

Answer:

110.9\ ft^{2}

Step-by-step explanation:

we know that

If the triangle of the figure is a regular polygon

then

Is an equilateral triangle

Remember that

The equilateral triangle has three equal sides and three equal interior angles

The measure of each interior angle is 60 degrees

To find the area of the equilateral triangle apply the law of sines

A=\frac{1}{2} b^{2}sin(60\°)

we have that

b=16\ ft

substitute

A=\frac{1}{2} (16^{2})sin(60\°)=110.9\ ft^{2}

8 0
3 years ago
What is the square root of 50 rounded to the nearest hundredth?
tamaranim1 [39]
Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.
8 0
3 years ago
Someone please help me
Alexxandr [17]
The answer is C since the 1 in the square root is a horizontal shift to the left by one and a vertical shift up by 7
5 0
3 years ago
What is the range of the function y = x2? ​
den301095 [7]

The range of the function y = x2 is all real numbers, y, such that y ≥ 0.

3 0
3 years ago
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